CODEWITHSUNDEEP
pythonpython-3.xpython-requestsurlliburllib2
Rahul
Rahul

Reputation: 537

requests.exceptions.MissingSchema: Invalid URL Python API Get request

I am trying to pull the data using get request through the below URL and I'm getting below error.

I'm not understanding what is the issue with the URL.

Any help would be appreciated

import requests
from requests.auth import HTTPBasicAuth 
import json
import urllib.parse

url = """https://msi.abc.com/admin/ui/feedbackCSV/reports
/5d14de32309baf0001501fb7 ?reports[]=pageviews&reports[]=
searches&from=Oct 1 2020&to=Oct 2 2020"""

encode_url = urllib.parse.quote(url,encoding='utf-8')

response = requests.get(encode_url,auth = HTTPBasicAuth('[email protected]', 'Summer2020')) 
print(response.content)

Error

raise MissingSchema(error) requests.exceptions.MissingSchema: Invalid URL 'https%3A%2F%2Fmsi.abc.com%2Fadmin%2Fui%2FfeedbackCSV%2Freports%0D%0A%2F5d14de32309baf0001501fb7%20%3Freports%5B%5D%3Dpageviews%26reports%5B%5D%3D%0D%0Asearches%26from%3DOct%201%202020%26to%3DOct%202%202020': No schema supplied. Perhaps you meant http:https%3A%2F%2Fmsi.abc.com%2Fadmin%2Fui%2FfeedbackCSV%2Freports%0D%0A%2F5d14de32309baf0001501fb7%20%3Freports%5B%5D%3Dpageviews%26reports%5B%5D%3D%0D%0Asearches%26from%3DOct%201%202020%26to%3DOct%202%202020?

Upvotes: 2

Views: 7588

Answers (1)

Harshana
Harshana

Reputation: 5496

This might be due to that you pass the whole URL to the urllib.parse.quote function. Try passing the params only to the urllib.parse.quote or use requests params like in the below example:

import requests
from requests.auth import HTTPBasicAuth 
import json
import urllib.parse

url = "https://msi.abc.com/admin/ui/feedbackCSV/reports/5d14de32309baf0001501fb7"
payload = {'reports[]':'pageviews', 'reports[]':'searches','from':'Oct 1 2020', 'to':'Oct 2 2020' }

authParams = HTTPBasicAuth('[email protected]', 'Summer2020')

response = requests.get(url,params=payload, auth =authParams ) 
print(response.content)

Upvotes: 2

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