CODEWITHSUNDEEP
pythonlist
tapas kumar
tapas kumar

Reputation: 21

Compare two lists element-wise and return the approximate value

I have two list as given below:

list1 = ['17_12_29', '17_08_04']

list2 = ['17_12_29_xyz','2017_12_29_abc', '17_08_04_mnp','17_08_04_mnp2',
         '2017_08_04_def', '17_08_05_pqr']

I want to compare the two list element wise and expecting the result as given below:-

res = ['17_12_29_xyz','2017_12_29_abc', '17_08_04_mnp','17_08_04_mnp2','2017_08_04_def'].

We have different library are available to get the result, but my constraint to use python code only.

Upvotes: 0

Views: 2104

Answers (4)

fireball.1
fireball.1

Reputation: 1521

You might wanna use in for comparison:

res=[]
for i in list1:
    for j in list2:
        if i in j:
            res.append(j)

Upvotes: 0

DarrylG
DarrylG

Reputation: 17166

Using list comprehension and any

res = [x for x in list2 if any(y in x for y in list1)]

print(res) # Output: ['17_12_29_xyz', '2017_12_29_abc', '17_08_04_mnp', '17_08_04_mnp2', '2017_08_04_def']

Upvotes: 2

Menethan
Menethan

Reputation: 41

You can check if a string exists within another string in python.

res = []
for s2 in list2:
   for s1 in list1:
     if s1 in s2:
       res.append(s2)

Upvotes: 0

Shadowcoder
Shadowcoder

Reputation: 972

This should work:

res=[]
list1 = ['17_12_29', '17_08_04'] 
list2 = ['17_12_29_xyz','2017_12_29_abc', '17_08_04_mnp','17_08_04_mnp2', '2017_08_04_def', '17_08_05_pqr'] 
for item in list2:
    for j in list1:
        if j in item:
            res.append(item)
            break
print(res)

Upvotes: 0

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