CODEWITHSUNDEEP
python
KDR87
KDR87

Reputation: 73

Python: Having trouble with a code for class

Prompt: Many user-created passwords are simple and easy to guess. Write a program that takes a simple password and makes it stronger by replacing characters using the key below, and by appending "q*s" to the end of the input string.

i becomes !
a becomes @
m becomes M
B becomes 8
o becomes .

Ex:

If the input is:
mypassword

the output is:
[email protected]*s

What I have so far:

#assign variables

word = input()

password = ''

#checking for and modifying user's password if containing the characters: i, a, m, B, or o
for character in word:

    if(character=='i'): #if user's password contains the letter i change to !
        word += '!'
    
    elif(character=='a'): #if user's password contains the letter a change to @
        word += '@'
        
    elif(character=='m'): #if the user's password contains the letter m change to M
        word += 'M'
        
    elif(character=='B'): #if the user's password contains the letter B change to 8
        word += '8'
        
    elif(character=='o'): #if the user's password contains the letter o change to .
        word += '.'
        
password = (word + 'qs')

#output final password

print(password)

My output is messed up. I input the password as mypassword and the output is [email protected]

Can someone please help me by telling me where I'm messing up?

Upvotes: 1

Views: 36562

Answers (4)

Clay
Clay

Reputation: 1

I had the same question in my studies, and it was designed to test your knowledge in loops. While there are simpler ways of coding this, I feel this may be more along the lines of what the exercise is looking for.

word = input()
password = ''

for character in word:                 #Begin looping through string
    if character == 'i':               #If 'i' is present, replace with '!'
        word = word.replace('i', '!')
    elif character == 'a':             #Else If 'a' is present, replace with '@'
        word = word.replace('a', '@')
    elif character == 'm':             #Else If 'm' is present, replace with 'M'
        word = word.replace('m', 'M')
    elif character == 'B':             #Else If 'B' is present, replace with '8'
        word = word.replace('B', '8')
    elif character == 'o':             #Else If 'o' is present, replace with '.'
        word = word.replace('o', '.')
else:                                  #Changes have been made, append 'q*s'
    word += 'q*s'
    password = word                    #Set new password

print(password)

Upvotes: 0

MrsDaytona955
MrsDaytona955

Reputation: 1

word = input()
password = ''

# Modify characters i, a, m, B, and o in password
for character in word:
    if character == 'i':     # IF character equals 'i' change to '!'
        password += '!'
    elif character == 'a':   # ELSE IF character equals 'a' change to '@'
        password += '@'
    elif character == 'm':   # ELSE IF character equals 'm' change to 'M'
        password += 'M'
    elif character == 'B':   # ELSE IF character equals 'B' change to '8'
        password += '8'
    elif character == 'o':   # ELSE IF character equals 'o' change to '.'
        password += '.'
    else:                    # When symbols do not get replaced 
        password += character

print(password + 'q*s')      # Make password stronger by adding "q*s" to the end of 
                             # the input string

Upvotes: 0

warped
warped

Reputation: 9481

Following your original logic, you need to initialise a word to return, otherwise all characters get appended to your old password.

word = input()

password = ''

#checking for and modifying user's password if containing the characters: i, a, m, B, or o

for character in word: # update password rather than word

    if(character=='i'): #if user's password contains the letter i change to !
        password += '!'
    
    elif(character=='a'): #if user's password contains the letter a change to @
        password += '@'
        
    elif(character=='m'): #if the user's password contains the letter m change to M
        password += 'M'
        
    elif(character=='B'): #if the user's password contains the letter B change to 8
        password += '8'
        
    elif(character=='o'): #if the user's password contains the letter o change to .
        password += '.'
        
    else: # add else statement for when symbols do not get replaced 
        password += character

print(password)

Upvotes: 0

coderoftheday
coderoftheday

Reputation: 2075

You can use .replace()

word = 'mypassword'

word = word.replace('i','!')
word = word.replace('a','@')
word = word.replace('m','M')
word = word.replace('B','8')
word = word.replace('o','.')

word = word + 'q*s'

print(word)

>>> [email protected]*s

You can also put all the .replace() on one line,

word = word.replace('i','!').replace('a','@').replace('m','M').replace('B','8').replace('o','.')

Upvotes: 2

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