Chris
Chris

Reputation: 12191

Link not opening Safari

I'm making a basic RSS reader and it should be opening the link in Safari, but nothing happens when I click on the cell. Here is what I have:

 - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
//Navigation Logic:

int storyIndex = [indexPath indexAtPosition: [indexPath length] -1];
NSString *storyLink = [[stories objectAtIndex: storyIndex] objectForKey:@"link"];

//cleaning up the link...

storyLink = [storyLink stringByReplacingOccurrencesOfString:@" " withString:@""];
storyLink = [storyLink stringByReplacingOccurrencesOfString:@"/n" withString:@""];
storyLink = [storyLink stringByReplacingOccurrencesOfString:@"  " withString:@""];

NSLog(@"link: %@", storyLink);

//open in Safari
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:storyLink]];


}

Here is the console log:

 2011-06-27 20:03:51.817 ParadiseBeats[26927:207] all done
 2011-06-27 20:03:51.818 ParadiseBeats[26927:207] stories array had 20 items
 2011-06-27 20:03:53.758 ParadiseBeats[26927:207] link: technobuffalo.com/companies/apple/…

And where I put in the link:

 - (void)viewDidAppear:(BOOL)animated
 {
     [super viewDidAppear:animated];
if ([stories count] == 0) {
    NSString *path = @"http://www.technobuffalo.com/feed/";
    [self parseXMLFileAtURL:path];
}

}

Here is the parsing code:

 -(void)parser:(NSXMLParser *) parser didStartElement:(NSString *) elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *__strong)qName attributes:(NSDictionary *__strong)attributeDict {

currentElement = [elementName copy];
if([elementName isEqualToString:@"item"]){
    //clear out story item caches...
    item = [[NSMutableDictionary alloc] init];
    currentTitle = [[NSMutableString alloc] init];
    currentDate = [[NSMutableString alloc] init];
    currentSummary = [[NSMutableString alloc] init];
    currentLink = [[NSMutableString alloc] init];

}

 }

  -(void)parser:(NSXMLParser *)parser didEndElement:(NSString *__strong)elementName namespaceURI:(NSString *__strong)namespaceURI qualifiedName:(NSString *__strong)qName {

if ([elementName isEqualToString:@"item"]) {
    [item setObject:currentTitle forKey:@"title"];
    [item setObject:currentLink forKey:@"link"];
    [item setObject:currentSummary forKey:@"summary"];
    [item setObject:currentDate forKey:@"date"];

    [stories addObject:[item copy]];
    NSLog(@"adding story: %@", currentTitle);
}


}

-(void)parser:(NSXMLParser *) parser foundCharacters:(NSString *__strong)string{
//save the characters for the current item

if ([currentElement isEqualToString:@"title"]) {
    [currentTitle   appendString:string];
}
else if ([currentElement isEqualToString:@"link"]) {
    [currentLink   appendString:string];
}
else if ([currentElement isEqualToString:@"pubDate"]) {
    [currentDate  appendString:string];
}
else if ([currentElement isEqualToString:@"description"]) {
    [currentSummary   appendString:string];
}


}

Upvotes: 1

Views: 562

Answers (2)

Gilbert
Gilbert

Reputation: 868

Your link, as showing in your log is

technobuffalo.com/companies/apple/…

instead of

http://technobuffalo.com/companies/apple/…

Please notice the difference: the "http://" prefix.

Your URL strings are missing the "http://" prefix.

Upvotes: 1

Mark Pauley
Mark Pauley

Reputation: 1485

Depak: your code above is wrong. You need to check for a prefix of http://, not a suffix. It should be:

if ( ![storyLink hasPrefix:@"http://"] ) {
    NSString* oldLink = storyLink;
    storyLink = [@"http://" stringByAppendingString:oldLink];
}

Chris: when you create the NSURL from the NSString, store that in a local variable and log that. If I'm right, the NSURL creation failed and you're currently passing NULL into -openURL. Have you tried opening a known-good NSURL:

[[UIApplication sharedApplication] openURL: [NSURL URLWithString: @"http://www.apple.com"]];

Upvotes: 2

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