CODEWITHSUNDEEP
pythoncharacter-encoding
R J Funnel404
R J Funnel404

Reputation: 93

Python JSON encoding invalid json format

i've stucked, i have a json with symbols like ' in values and syntax with ' and "

Example mix double qoute and single qoutelink

json ={
 'key': "val_'_ue",
 'secondkey': 'value'
}

With json loads and json dumps i got a str type not a dict to iterate, any ideas how i get it fixed?

        print(postParams)# = {'csrf-token': "TOKEN_INCLUDES_'_'_symbols", 'param2': 'params2value'}

        jsn_dict2 = json.loads(json.dumps(postParams))
        print(type(jsn_dict2)) # ERROR HERE why str and not dict
        
        for key, val in jsn_dict2.items():
            print("key="+str(key))

Upvotes: 1

Views: 1903

Answers (2)

adir abargil
adir abargil

Reputation: 5745

you dont need to dumps() an already string json data:

jsn_dict = json.loads(json.dumps(res))

should be :

jsn_dict = json.loads(res)

UPDATE

according to comments the data is looks like so:

postParams = "{'csrf-token': \"TOKEN_INCLUDES_'_'_symbols\", 'add-to-your-blog-submit-button': 'add-to-your-blog-submit-button'}"

so i found an library that can help damaged json string like this one:

  • first run :

    pip install demjson

  • then this code can help you:

from demjson import decode
data = decode(postParams)
data
>>> {'csrf-token': "TOKEN_INCLUDES_'_'_symbols",
 'add-to-your-blog-submit-button': 'add-to-your-blog-submit-button'}

Upvotes: 1

Harsha Vardhan Gundapaneni
Harsha Vardhan Gundapaneni

Reputation: 46

In your json u have missed the "," comma separation between two keys. The actual structure of the JSON is

json_new ={ 'key': "val_'_ue", 'secondkey': 'value' }

use

json_actual=json.dumps(json_new)

to read,

json_read=json.loads(json_actual)

Upvotes: 0

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