CODEWITHSUNDEEP
python
user14187369
user14187369

Reputation:

How to find the last matched key by comparing with list and dictionary

A list and dictionary is below

main_list = ["projecttype","emptype","Designation"]
sample = {"query": {
      "emptype":["Manager"],"projecttype":["temp"],
    "from": [
      "0"
    ],
    "q": [
      ""
    ],
    "size": [
      "4"
    ]
  }}

  1. How to find from the main_list which key is last "entered key" in sample dictionary

  2. How to find from the main_list which key is first "entered key" in sample dictionary

In this particular scenario

  1. "projecttype" is my output for last entered key which matches
  2. emptype is my output for first entered key which matches

Upvotes: 0

Views: 66

Answers (2)

Erick Rodriguez
Erick Rodriguez

Reputation: 198

You could do this in a cuple of lines and have the order of all the elements that are contained in your main_list as follow:

sample_query_keys = list(sample['query'].keys())
result = {sample_query_keys.index(main_key):main_key for main_key in main_list if main_key in sample_query_keys}

Then you can get the first and last item as follow:

print(result[0], result[len(result)-1])

Keep in mind that this will only work if the dictionary is ordered. That is only possible in Python 3.7 onwards. For previous versions, you would need to use OrderedDict.

Upvotes: 0

mazore
mazore

Reputation: 1024

You can iterate through it and test if the keys are in your main_list. Save every key that is in main_list and after the for loop you will have the last entered key.

main_list = ["projecttype","emptype","Designation"]
sample = {
    "query": {
        "emptype": ["Manager"],
        "projecttype": ["temp"],
        "from": ["0"],
        "q": [""],
        "size": ["4"]
    }
}

first = None
last = None
for key, value in sample['query'].items():
    if key in main_list:
        if first is None:
            first = key
        last = key
print('First:', first)
print('Last:', last)

Upvotes: 1

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