CODEWITHSUNDEEP
c++templatesc++17typename
th3g3ntl3man
th3g3ntl3man

Reputation: 2106

C++ - Get typename of a template where that class is used as another template

I would like to get the typename of a class template from another class that use a tamplate based on the first class.

I have wrote a class like so:

template<typename T>
class class_a {
  ...
}

I would like to do something that:

template<class class_a>
class class_b {
  std::vector<class_a.T> arr;
  ...
}

Upvotes: 3

Views: 989

Answers (1)

Sam Varshavchik
Sam Varshavchik

Reputation: 118292

The easiest way to do this is to have your templates "cooperate" with each other, and for class_a to "help" the other template:

template<typename T>
class class_a {

public:
   typename T type_t;
};

And then:

template<class class_a>
class class_b {
  std::vector<typename class_a::type_t> arr;
  ...
};

You will find this to be a pretty much standard design pattern in the C++ library itself. Most C++ containers, for example, define value_type, so if we changed the typedef to value_type:

template<typename T>
class class_a {

public:
   typename T value_type;
};

And then:

template<class class_a>
class class_b {
  std::vector<typename class_a::value_type> arr;
  ...
};

Then if your class_b were to be instantiated using a std::list, for example:

class_b<std::list<char>> b;

Then your arr will end up being std::vector<char>.

An alternative that does not require this "cooperation" would be to use a helper template with specialization, in order to avoid having to explicitly declare a typedef alias. However this is the simplest solution unless you have some specific reason not to do things this way.

Upvotes: 6

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