CODEWITHSUNDEEP
pythonsorting
Ibrahim Quraish
Ibrahim Quraish

Reputation: 4099

How to sort a list to get all lowercase alphabet words before uppercase?

I have followed this link and tried various probabilities to get the desired output

sorted(['aa', 'bb', '_dd', 'BB', 'AA'])
['AA', 'BB', '_dd', 'aa', 'bb']

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=True)
['bb', 'aa', '_dd', 'BB', 'AA']

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], key=str.lower)
['_dd', 'aa', 'AA', 'bb', 'BB']

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=True, key=str.lower)
['bb', 'BB', 'aa', 'AA', '_dd']

sorted(sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=False), key=str.lower)
['_dd', 'AA', 'aa', 'BB', 'bb']

sorted(sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=True), key=str.lower)
['_dd', 'aa', 'AA', 'bb', 'BB']

sorted(sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=True), key=lambda x: (x.lower(), x.swapcase()))
['_dd', 'aa', 'AA', 'bb', 'BB']

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], key=str.istitle)
['aa', 'bb', '_dd', 'BB', 'AA']

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=True, key=str.istitle)
['aa', 'bb', '_dd', 'BB', 'AA']

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=False, key=str.istitle)
['aa', 'bb', '_dd', 'BB', 'AA']

sorted(sorted(['aa', 'bb', '_dd', 'BB', 'AA']), key=str.istitle)
['AA', 'BB', '_dd', 'aa', 'bb']

sorted(sorted(['aa', 'bb', '_dd', 'BB', 'AA'], reverse=True), key=str.istitle)
['bb', 'aa', '_dd', 'BB', 'AA']

But I need the output to be in this order

['_dd', 'aa', 'bb', 'AA', 'BB']

Upvotes: 1

Views: 99

Answers (1)

kirbyfan64sos
kirbyfan64sos

Reputation: 10727

Try this:

sorted(['aa', 'bb', '_dd', 'BB', 'AA'], key=lambda s: (s.upper() == s, s))

Tuples are sorted by its first item before the second, and bools are sorted as False before true, so the s.upper() == s will sort all non-uppercase ones before the others.

Note that, if your purpose is language-oriented sorting, you should probably look into using key=functools.cmp_to_key(locale.strcoll) or similar instead.

Upvotes: 2

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