CODEWITHSUNDEEP
python
Adyz
Adyz

Reputation: 11

Keys don't exist in dictionary

I'm learning python, now learning about dictionaries.

I think I understand it quite well, however I need help solving this code:

fib = {1: 1, 2: 1, 3: 2, 4: 3}
print(fib.get(4, 0) + fib.get(7, 5))

The answer of this is 8. But why? It should be 3 right? Because 7 and 5 dont even exist in the dictionary and it should return None.

Upvotes: 1

Views: 293

Answers (2)

sudeep Timsina
sudeep Timsina

Reputation: 1

you can have a look over here the fib.get(7,7) is providing with the output of 7 as the second argument is considered to be default value it gives out 7 over there just like just above there fib.get(6,6) gives out 6 as an output. so when you provide fib.get(7,5) the second argument comes over there and gives out output adding with the value of first fib.get(4,3) which is 3 and final output of fib.get(4,0) +fib.get(7,5)] will be 8.. image makes you more clear

Upvotes: 0

Aplet123
Aplet123

Reputation: 35512

The second argument of get is the default value: if the key isn't found, it'll return the second argument instead of None. So, fib.get(7, 5) will not find 7 and default to 5, leaving you with 3+5 which is 8.

Upvotes: 3

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