CODEWITHSUNDEEP
cscanf
Solken
Solken

Reputation: 23

Why does scanf("%[^\n]\n", titre); ask me for a third input

I'm on Win10, currently learning C, and I quite don't understand my output (EKEKEKEKE) for a simple exercice that ask for an input and give as output the same string without vowels.

inputBLABLABLA
EKEKEKE
outputB.L.B.L.B.L.
inputBLABLABLA
outputK.K.K.

int main()
{
    for (int i = 0; i < 2; i = i + 1)
    {

        printf("input");
        char titre[101] = {0};
        scanf("%[^\n]\n", titre);


        int j = 0;
        char t = titre[0];

        printf("output");

        while ((t != '\0') && (j < 101))
        {
            if ((t != 'A')
                && (t != 'E')
                && (t != 'I')
                && (t != 'O')
                && (t != 'U')
                && (t != 'Y')
                && (t != ' '))
            {
                printf("%c.", t);
            }
            j = j + 1;
            t = titre[j];
        }
        if (i == 0)
        {
            printf("\n");
        }
    }
}

Upvotes: 2

Views: 111

Answers (2)

Micrified
Micrified

Reputation: 3650

Well, the problem is really with the scanf() regular expression. Mainly that you're eating all characters except the newline, until you hit a newline. However, after matching all that scanf() still doesn't return because it is still 'matching' more. By changing that expression so that am not matching a newline but an arbitrary character (which should be a newline), I'm able to get it to respond as you expect. I've also modified your code slightly to move some functionality to another function:

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

#define INPUT_COUNT  2
#define BUFFER_SIZE  100

int is_vowel (char c)
{
    const char *vowels = "AEIOUY ";
    for (const char *s = vowels; *s != '\0'; s++) {
        if (toupper(c) == *s) {
            return 1;
        }
    }
    return 0;
}

int main ()
{
    for (int i = 0; i < INPUT_COUNT; i++) {
        char c, titre[BUFFER_SIZE + 1] = {0};

        // Scan in a line.
        printf("Input:\t");
      
        // %100 <- Limit 100 characters. %c <- Trick to get around newline issue
        scanf(" %100[^\n]%c", titre, &c);

        printf("Output:\t");
        for (int j = 0; j < BUFFER_SIZE && titre[j] != '\0'; j++) {

            if (!is_vowel(titre[j])) {
                printf("%c.", titre[j]);
            }
        }
        putchar('\n');
    }
}

Upvotes: 1

MED LDN
MED LDN

Reputation: 669

You chould use gets to read a string like this :

int main()
{
    for (int i = 0; i < 2; i = i + 1)
   {
       printf("input :");
       char titre[101] = {0};
       gets(titre);
       int j = 0;
       char t = titre[0];
       printf("output :");

       while ((t != '\0') && (j < 101))
       {
          if ((t != 'A')&&(t != 'E')&&(t != 'I')&&(t != 'O')&&(t != 'U')&&(t != 'Y')&&(t != ' '))
          {
              printf("%c.", t);
          }
           j = j + 1;
           t = titre[j];
       }
       if (i == 0)
       {
           printf("\n");
       }
    }
  }

Upvotes: 0

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