CODEWITHSUNDEEP
python
Zipen
Zipen

Reputation: 15

Why do I keep Getting ELIF Invalid Syntax Error?

Getting an ELIF syntax error, I'm new to python and i have no idea why I'm I getting this error

print("Résolution de l'équation du second degré : ax² + bx + c = 0")
chaineA= input("Coefficient de a ?: ")
a= float(chaineA)
chaineB= input("Coefficient de b ?: ")
b= float(chaineB)
chaineC= input("Coefficient de c ?: ")
c= float(chaineC)
delta=((b**2)-(4*a*b))
solut1= (-b + (delta**0.5)/(2*a))
solut2= (-b - (delta**0.5)/(2*a))
solut3= (-b/2*a)

if delta >= 0.0:
    print("Deux solutions: ")
    print("x1 =" , solut1)
    print("x2 =" , solut2)
elif delta = 0.0:
    print("Une solution")
    print("x =" , solut3)
elif delta <= 0.0:
    print("Pas de solution")

Thanks in advance

Upvotes: 0

Views: 211

Answers (3)

xl3ehindTim
xl3ehindTim

Reputation: 127

By only using one = in your elif it thinks you are trying to assign 0.0 to delta. It should be:

elif delta == 0.0

This will compare delta to 0.0 and if they are the same run your code in the elif.

Upvotes: 1

ombk
ombk

Reputation: 2111

print("Résolution de l'équation du second degré : ax² + bx + c = 0")
chaineA= input("Coefficient de a ?: ")
a= float(chaineA)
chaineB= input("Coefficient de b ?: ")
b= float(chaineB)
chaineC= input("Coefficient de c ?: ")
c= float(chaineC)
delta=((b**2)-(4*a*b))
solut1= (-b + (delta**0.5)/(2*a))
solut2= (-b - (delta**0.5)/(2*a))
solut3= (-b/2*a)

if delta >= 0.0: # here it should be > only
    print("Deux solutions: ")
    print("x1 =" , solut1)
    print("x2 =" , solut2)
elif delta = 0.0: # first error here it should be elif delta == 0:
    print("Une solution")
    print("x =" , solut3)
else: #this could be made else. no need to put a condition.
    print("Pas de solution")

Upvotes: 0

kishore Rajendran
kishore Rajendran

Reputation: 278

you have used single = instead of ==.

elif delta == 0.0:

Upvotes: 1

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