CODEWITHSUNDEEP
python
Max888
Max888

Reputation: 3760

Most recent date for list sorted by values

I have a list that looks roughly like this:

mylist = [[2, 20200101], [2, 20200108], [2, 20200101], [1, 20200110], [1, 20200101]]

It is a list of lists, each of which has a value as the first element, and a date as the second. I want to choose the list which first has the highest value (2 in this case) then the most recent date, (20200108 - 8th Jan 2020, in this case) I know you can pass a lambda function to the built in max() function, like below, but I am not sure how to handle choosing the max of first the value, then the date?

max(mylist, key=lambda x: x[0])

Upvotes: 0

Views: 318

Answers (2)

Aplet123
Aplet123

Reputation: 35502

In Python, lists compare lexicographically by default. This means that the first element is compared, then the next, and so on, which is exactly what you want. (As a side note, shorter lists will be less than longer lists) So, you can just max without a key:

max(mylist)

Upvotes: 1

Kuldeep Singh Sidhu
Kuldeep Singh Sidhu

Reputation: 3856

The default max works from the first index to the last in an iterable sorting.

mylist = [[2, 20200101], [2, 20200108], [2, 20200101], [1, 20200110], [1, 20200101]]
max(mylist)

OR

You can pass two keys!

mylist = [[2, 20200101], [2, 20200108], [2, 20200101], [1, 20200110], [1, 20200101]]
max(mylist, key=lambda x: (x[0], x[1]))

Upvotes: 0

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