Matze
Matze

Reputation: 3

How to sum up arrays to then find the minimum

Here's my problem: I have 2 sheets in my document (lets call them Sheet 1 and Sheet 2). They contain similar stuff and both look like this (Names may differ, as well as values):

enter image description here

Column A, C, D and F contain times (in m:ss). Column B and E both calculate the time-difference between NameX and NameY and add ">, < or ~ ~" depending on the actual difference (ignore the coloring).

Now here comes my problem: I want to find 3 minima (on Sheet 3). Minimum 1 is easy, as I can just use this function (it automatically filters out column B and E):

MIN('Sheet 1'!A2:F2, 'Sheet 2'!A2:F2)

Minimum 2 and 3 are were I struggle.

Minimum 2: Using the example values, I want to find the minimum of (1:01+1:02), (1:02+1:05), (1:01+1:01) and (1:01+1:02) (+ whatever times are on sheet 2). Result should be 2:02.

Minimum 3: Again, using the example values, I want to find the minimum of (1:01+1:02+1:03), (1:02+1:05+0:30), (1:01+1:01+1:12) and (1:01+1:02+2:02) (+ whatever times are on sheet 2). Result should be 2:37.

I am currently using this formula (for minimum 3):

=MIN(
IFERROR(FILTER(IFERROR(ARRAYFORMULA({'Sheet 1'!A2:F2}+{'Sheet 1'!A3:F3}+{'Sheet 1'!A4:F4})),
IFERROR(ARRAYFORMULA({'Sheet 1'!A2:F2}+{'Sheet 1'!A3:F3}+{'Sheet 1'!A4:F4}))<>0)),
IFERROR(FILTER(IFERROR(ARRAYFORMULA({'Sheet 2'!A2:F2}+{'Sheet 2'!A3:F3}+{'Sheet 2'!A4:F4})),
IFERROR(ARRAYFORMULA({'Sheet 2'!A2:F2}+{'Sheet 2'!A3:F3}+{'Sheet 2'!A4:F4}))<>0))
)

Some notes: The inner IFERROR-function is needed to filter out errors that obviously occur when trying to add up column B and E. FILTER-function filters out columns that are empty (there's none in this example). The second IFERROR-function filters out FILTER-functions that return an error when they get no input at all (all columns in a sheet are empty). I want to filter of these since I don't want to get 0:00 as result

My problem is this: In my actual sheet I have 11 sheets with 16 rows to add up, but I don't want to use the formula above and create an insane monster of a formula that would x-times as long as the formula above.

So my question is: Is there an easier way to solve this problem for mimimum 3 (and therefore 4, 5, 6 ...) that I'm not seeing?

Upvotes: 0

Views: 115

Answers (1)

MattKing
MattKing

Reputation: 7783

It's a little monstrous, but this might work:

=MIN(FILTER({
MMULT(SEQUENCE(1,ROWS(Sheet1!A2:F),1,0),N(Sheet1!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet2!A2:F),1,0),N(Sheet2!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet3!A2:F),1,0),N(Sheet3!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet4!A2:F),1,0),N(Sheet4!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet5!A2:F),1,0),N(Sheet5!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet6!A2:F),1,0),N(Sheet6!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet7!A2:F),1,0),N(Sheet7!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet8!A2:F),1,0),N(Sheet8!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet9!A2:F),1,0),N(Sheet9!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet10!A2:F),1,0),N(Sheet10!A2:F));
MMULT(SEQUENCE(1,ROWS(Sheet11!A2:F),1,0),N(Sheet11!A2:F))},
{1,0,1,1,0,1}))

Upvotes: 1

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