Reputation: 1
I am completely new in React Native and I am trying to improve my self with some making sample apps. For this scenario, I only want that when the Button
is pressed, the state and the value of the toggle change, such as CLOSED
and OPEN
. And Make Open
is not changed. Now, I have three class components. I am not going to give App's class. I've alread completed it. In this class, I have added a prop:
class A extends Component
{
constructor(props)
{
super(props);
this.state = {change: true};
}
render(){
return(
<View>
<View ...
<Text>CLOSED</Text>
</View>
</View>
);
}
}
Here is my second class B:
class B extends Component
{
state = {isOpen : false};
render()
{
onPress = () => {
...
})
}
return(
<View>
<View ...
<A/>
<Button
title="Make Open"
onPress={this.onPress}
/>
</View>
</View>
);
}
}
I am struggling with the prop. My question is that I want to pass the isOpen
value from the class B
's state to class A
by use of this prop. I think that I could not create state in class B
. What is the easiest way to solve this problem ? If I gave not enough information, sorry for that.
Upvotes: 0
Views: 46
Reputation: 11
When you call component A from component B, you have to pass your state like so:
<A isOpen={this.state.isOpen} />
Then in component A, you can simply access it with props.isOpen.
Upvotes: 1