Reputation: 77
Given two arrays, where array one has variables and array two contains the variable's values, I want to get all possible combinations of those two arrays, for example:
String[] arr = {"E", "A", "C"};
String[] val = {"true", "false"};
Array arr
can hold as many variables as possible, and val
too.
Desired output:
E true A true C true
E true A true C false
E true A false C true
E true A false C false
E false A true C true
E false A true C false
E false A false C true
E false A false C false
I tried a recursion approach:
import java.util.*;
class Main {
public static void main(String[] args) {
String[] arr = {"E", "A", "C"};
String[] val = {"true", "false"};
printAll(arr, val, 0);
}
public static void printAll(String[] x, String[] y, int index) {
if (x.length == 0) {
return;
}
for (String d : x) {
for (String val : y) {
System.out.print(d + " " + val + " ");
String[] arr2 = Arrays.copyOfRange(x, index + 1, x.length);
printAll(arr2, y, index);
}
}
System.out.println();
}
}
But the output that I get is:
E true A true C true C false
A false C true C false
C true C true C false
C false C true C false
E false A true C true C false
A false C true C false
C true C true C false
C false C true C false
A true A true C true C false
A false C true C false
C true C true C false
C false C true C false
A false A true C true C false
A false C true C false
C true C true C false
C false C true C false
C true A true C true C false
A false C true C false
C true C true C false
C false C true C false
C false A true C true C false
A false C true C false
C true C true C false
C false C true C false
I want to be able to save each correct line as an element in an ArrayList
but first I want to figure out how to print each line correctly.
EDIT: The second array is not constant, it differs between each variable:
String[] arr = {"E", "A", "C"};
String[] valE = {"true", "false"};
String[] valA = {"true", "false"};
String[] valB = {"set", "noset", "maybe"};
Obviously this wont work in recursion as I need to send each array along side the variables array, I achieve this by creating a Variables
object which contains its specific values, so the loop would be:
for (String d : x) {
for (String val : d.getValues()) {...}
}
This is not relevant to the main question, I simply reduced the question to a simple case where each variable has two possible values.
Upvotes: 0
Views: 1377
Reputation: 1
import java.util.*;
public class Solution {
public static String[] combineAllStrings(String[] s1, String[] s2) {
int result =0;
int N = s1.length*s2.length;
String[] combineString= new String[N];
for (int i=0;i<s1.length;i++){
for (int j=0;j<s2.length;j++){
combineString[result]=s1[i]+s2[j];
System.out.println(combineString);
result =result+1;
}
}
return combineString;
}
public static void main(String args[]) {
String input1[] = {"a", "c", "e"};
String input2[] = {"b", "d", "f"};
String output[] = {"ab", "ad", "af", "cb", "cd", "cf", "eb", "ed", "ef"};
assert Arrays.equals(combineAllStrings(input1, input2), output) : "Expect [\"ab\", \"ad\", \"af\", \"cb\", \"cd\", \"cf\", \"eb\", \"ed\", \"ef\"] for input1 = [\"a\", \"c\", \"e\"] and input2 = [\"b\", \"d\", \"f\"]";
System.out.println("All test cases in main function passed");
}
}
Upvotes: 0
Reputation:
You can generate a 2d array of possible combinations using map
and reduce
methods:
String[] array = {"E", "A", "C"};
String[] values = {"true", "false"};
String[][] combinations = Arrays.stream(array)
// represent each string as a 2d array of possible combinations
.map(str -> Arrays.stream(values).map(bool -> new String[]{str, bool})
// stream of 2d arrays
.toArray(String[][]::new))
// intermediate output
.peek(comb -> System.out.println(Arrays.deepToString(comb)))
// reduce stream of 2d arrays to a single 2d array
.reduce((arr1, arr2) -> Arrays.stream(arr1)
// combinations of inner arrays
.flatMap(inner1 -> Arrays.stream(arr2)
// merge two inner arrays into one
.map(inner2 -> Stream.of(inner1, inner2)
.flatMap(Arrays::stream)
.toArray(String[]::new)))
// array of combinations
.toArray(String[][]::new))
// otherwise an empty 2d array
.orElse(new String[0][]);
// final output
Arrays.stream(combinations).map(Arrays::toString).forEach(System.out::println);
Intermediate output:
[[E, true], [E, false]]
[[A, true], [A, false]]
[[C, true], [C, false]]
Final output:
[E, true, A, true, C, true]
[E, true, A, true, C, false]
[E, true, A, false, C, true]
[E, true, A, false, C, false]
[E, false, A, true, C, true]
[E, false, A, true, C, false]
[E, false, A, false, C, true]
[E, false, A, false, C, false]
See also: Outputting permutations of ArrayList using recursion
Upvotes: 2
Reputation:
You can iteratively generate all possible combinations of two arrays using streams
as follows:
String[] arr = {"E", "A", "C"};
String[] val = {"true", "false"};
// an array of possible combinations
String[] comb = Arrays.stream(arr)
.map(e -> Arrays.stream(val)
// append each substring
// with possible combinations
.map(v -> e + " " + v + " ")
// return Stream<String[]>
.toArray(String[]::new))
// reduce stream of arrays to a single array
// by sequentially multiplying array pairs
.reduce((arr1, arr2) -> Arrays.stream(arr1)
.flatMap(str1 -> Arrays.stream(arr2)
.map(str2 -> str1 + str2))
.toArray(String[]::new))
.orElse(null);
// output
Arrays.stream(comb).forEach(System.out::println);
E true A true C true
E true A true C false
E true A false C true
E true A false C false
E false A true C true
E false A true C false
E false A false C true
E false A false C false
See also: Generate all possible string combinations by replacing the hidden “#” number sign
Upvotes: 1