Reputation: 1401
We have a situation that I have been able to recreate with the following simple example. I have the following two sample tables:
CREATE TABLE contact_info
(
id INT UNSIGNED AUTO_INCREMENT,
priContactId INT,
secContactId INT,
blahBlah VARCHAR(32),
PRIMARY KEY(id)
);
and
CREATE TABLE name_lookup
(
id INT UNSIGNED AUTO_INCREMENT,
contactID INT,
contactName VARCHAR(32),
PRIMARY KEY(id)
);
I populate them as follows:
INSERT INTO contact_info(priContactId, secContactId, blahBlah) VALUES(1, 3, "Team A"), (4, 2, "Team B");
INSERT INTO name_lookup(contactID, contactName) VALUES(1, "John Doe"), (2, "Mary Smith"), (3, "Jose Garcia"), (4, "Larry Brown");
Obviously, the contents of the tables are as follows:
+----+--------------+--------------+----------+
| id | priContactId | secContactId | blahBlah |
+----+--------------+--------------+----------+
| 1 | 1 | 3 | Team A |
| 2 | 4 | 2 | Team B |
+----+--------------+--------------+----------+
+----+-----------+-------------+
| id | contactID | contactName |
+----+-----------+-------------+
| 1 | 1 | John Doe |
| 2 | 2 | Mary Smith |
| 3 | 3 | Jose Garcia |
| 4 | 4 | Larry Brown |
+----+-----------+-------------+
We would like to perform a JOIN operation so that we get output like this:
+-------------+-------------+--------+
| John Doe | Jose Garcia | Team A |
+-------------+-------------+--------+
| Larry Brown | Mary Smith | Team B |
+-------------+-------------+--------+
The join constraints for both the priContactId
and secContactId
columns are the same and I am having tough time figuring out what the JOIN query should look like.
FYI, we are using MySQL version 5.6.49
.
Upvotes: 0
Views: 112
Reputation: 1270773
This would normally be handled with two joins. You don't have not null
constraints on the two contacts, so I would suggest outer joins:
select nl_pri.contactName as PrimaryName, nl_sec.contactName as SecondaryName,
ci.blahblah
from contact_info ci left join
name_lookup nl_pri
on ci.priContactId = nl_pri.contactId left join
name_lookup nl_sec
on c.secContactId = nl_sec.contactId;
Notes:
left join
keeps all contacts, even those that don't have both primary and secondary.name_lookup
table.Upvotes: 1
Reputation: 42739
Two separate columns needs 2 separate table copies join.
SELECT t1.contactName name1, t2.contactName name1, t3.blahBlah team
FROM name_lookup t1
JOIN name_lookup t2
JOIN contact_info t3 ON t1.contactID = t3.priContactId
AND t2.contactID = t3.secContactId
Upvotes: 1