CODEWITHSUNDEEP
swiftfunctionrandom
Nathanael Tse
Nathanael Tse

Reputation: 363

Smart way to pick a random function

I am trying to pick and run a random function in swift.

Currently I have implemented a switch case like this

  switch Int.random(in: 1...2) {
                            case 1:   functionOne()
                            case 2:   functionTwo()
                            default:  print("error")
                            }

if there are more options the code gets really excessive.

How can I improve the code to make it save the extra lines? The optimum would be:

  [functionOne(), functionTwo()].randomElement()

This does not work but just runs the last element in the array. Is there a way to put functions in an array and let them run?

Upvotes: 0

Views: 99

Answers (1)

Duncan C
Duncan C

Reputation: 131471

If you want the probability of the different functions to be different then your switch statement would be a good choice:

switch Int.random(in: 1...100) {
                        case 1...10:   functionOne() //10% of calls
                        case 11...100: functionTwo() //90% of calls 
                        default:       noFunction()
                        }

If you want them all to be equally as likely then Matt's approach seems cleaner:

let functions = [functionOne, functionTwo]
(functions.randomElement()!)()

Upvotes: 1

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