Reputation: 1309
When I do sizeof(int)
in my C#.NET project I get a return value of 4. I set the project type to x64, so why does it say 4 instead of 8? Is this because I'm running managed code?
Upvotes: 49
Views: 37785
Reputation: 10875
There are various 64-bit data models; Microsoft uses LP64 for .NET: both longs and pointers are 64-bits (although C-style pointers can only be used in C# in unsafe
contexts or as a IntPtr
value which cannot be used for pointer-arithmetic). Contrast this with ILP64 where ints are also 64-bits.
Thus, on all platforms, int
is 32-bits and long
is 64-bits; you can see this in the names of the underlying types System.Int32
and System.Int64
.
Upvotes: 45
Reputation: 69352
int
means Int32
in .NET languages. This was done for compatibility between 32- and 64-bit architectures.
Here's the table of all the types in C# and what they map to .NET wise.
Upvotes: 28
Reputation: 347406
You may be thinking of an int
pointer or System.IntPtr
. This would be 8 bytes on an x64 and 4 bytes on an x86. The size of a pointer shows that you have 64-bit addresses for your memory. (System.IntPtr.Size
== 8 on x64)
The meaning of int
is still 4 bytes whether you are on an x86 or an x64. That is to say that an int
will always correspond to System.Int32
.
Upvotes: 14
Reputation: 22578
An Int32
is 4 bytes on x86 and x64. An Int64
is 8 bytes either case. The C# int
type is just an alias for System.Int32
. Same under both runtime environments. The only type that does change depending on the runtime environment is an IntPtr
:
unsafe
{
var size = sizeof(IntPtr); // 4 on x86 bit machines. 8 on x64
}
Upvotes: 19
Reputation: 116421
Remember int
is just a compiler alias for the basic type Int32
. Given that it should be obvious why int
is only 32 bits on a 64 bit platform.
Upvotes: 6
Reputation: 351556
The keyword int
aliases System.Int32
which still requires 4 bytes, even on a 64-bit machine.
Upvotes: 53