CODEWITHSUNDEEP
javascripttypescriptdestructuring
Rahmani
Rahmani

Reputation: 877

How can I use object destruction as parameter in calling a function?

I have an object like this:

let a = { x: 3, y: '3', z: 'z' };

And an array like this:

let b = [{ x: 1, y: '1'}, { x: 2, y: '2' }];

How can I do something like this:

b.push({ x, y } = a);

Instead of this:

b.push({ x: a.x, y: a.y });

// or this:
const { x, y } = a;
b.push({ x, y });

Upvotes: 1

Views: 903

Answers (1)

Nina Scholz
Nina Scholz

Reputation: 386604

You need to return a new object with the destructured properties.

const
    getXY = ({x, y}) => ({ x, y }),
    a = { x: 3, y: '3', z: 'z' },
    b = [{ x: 1, y: '1'}, { x: 2, y: '2' }];

b.push(getXY(a));

console.log(b);

Upvotes: 1

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