Reputation: 443
My input data is structured as follows:
label_1
value_1
label_2
value_2
...
And my end goal is to read that data into a HashMap
My current working approach is to put even and odd lines in two separate vectors and then read from both vectors to add to Hashmap.
use std::io;
use std::io::prelude::*;
use std::collections::HashMap;
fn main() {
let mut labels: Vec<String> = Vec::new();
let mut values: Vec<String> = Vec::new();
let stdin = io::stdin();
/* Read lines piped from stdin*/
for (i, line) in stdin.lock().lines().enumerate() {
if i % 2 == 0 {
/* store labels (even lines) in labels vector */
labels.push(line.unwrap());
} else {
/* Store values (odd lines) in values vector */
values.push(line.unwrap());
}
}
println!("number of labels: {}", labels.len());
println!("number of values: {}", values.len());
/* Zip labels and values into one iterator */
let double_iter = labels.iter().zip(values.iter());
/* insert (label: value) pairs into hashmap */
let mut records: HashMap<&String, &String> = HashMap::new();
for (label, value) in double_iter {
records.insert(label, value);
}
}
I would like ask how to achieve this result without going though an intermediary step with vectors ?
Upvotes: 1
Views: 2274
Reputation: 59892
You can use .tuples()
from the itertools
crate:
use itertools::Itertools;
use std::io::{stdin, BufRead};
fn main() {
for (label, value) in stdin().lock().lines().tuples() {
println!("{}: {}", label.unwrap(), value.unwrap());
}
}
See also:
Upvotes: 3
Reputation: 4133
You can manually advance an iterator with .next()
use std::io;
use std::io::prelude::*;
use std::collections::HashMap;
fn main() {
let stdin = io::stdin();
let mut lines = stdin.lock().lines();
let mut records = HashMap::new();
while let Some(label) = lines.next() {
let value = lines.next().expect("No value for label");
records.insert(label.unwrap(), value.unwrap());
}
}
Upvotes: 2
Reputation: 2865
How about:
fn main() {
let lines = vec![1,2,3,4,5,6];
let mut records = std::collections::HashMap::new();
for i in (0..lines.len()).step_by(2) {
// make sure the `i+1` is existed
println!("{}{}", lines[i], lines[i + 1]);
records.insert(lines[i], lines[i + 1]);
}
}
Upvotes: 0