CODEWITHSUNDEEP
python
Carla
Carla

Reputation: 3390

Python: How to filter out elements from an array of strings which are starting with a certain pattern

I have an array of Strings. I'd like to evict all elements which start with a pattern. The pattern is contained in another array.

words=[] # contains the word lists

banned_words = ["http:","https:","mailto:"]

for word in words:

    if (word.startswith(banned_words)):
        continue

    addWord(word)

I'm not including the addWord function for simplicity, however my attempt was to use the startsWith against the array of banned words. But it does not work. I could loop on each banned_words element and it will eventually work. However, is there a simpler approach to remove elements from an array whose string starts with (array) ? Thanks

Upvotes: 0

Views: 798

Answers (2)

darkspine
darkspine

Reputation: 693

As Tomerikoo has said

>>> help(str.startswith)
startswith(...)
    S.startswith(prefix[, start[, end]]) -> bool

    Return True if S starts with the specified prefix, False otherwise.
    With optional start, test S beginning at that position.
    With optional end, stop comparing S at that position.
    prefix can also be a tuple of strings to try.

"prefix can also be a tuple of strings to try.". So it can also just be:

for word in words: 
    if word.startswith(tuple(banned_words))

Upvotes: 1

MetallimaX
MetallimaX

Reputation: 614

You can use list comprehension with a filter (more info here)

final = [word for word in words if not any(word.startswith(t) for t in banned_words)]

Upvotes: 1

Related Questions