CODEWITHSUNDEEP
pythonnumpy
Jasper Schumacher
Jasper Schumacher

Reputation: 11

How to create a random Matrix in Python without duplicating integers?

My current solution to create a random matrix is

matrix = np.random.randint(low=n, high=m, size=(x,y))

Do you know a solution to not use an integer twice? Thank you

Upvotes: 0

Views: 152

Answers (2)

alluppercase
alluppercase

Reputation: 354

If you don't want to use random choice, you can always just randomly pop from a list of integers.

import numpy as np
# define values 
n = 0
m = 20 
x = 3
y = 4 

integer_list = [i for i in range(n, m)]  # assuming m is exclusive 
matrix = np.zeros((x,y))
for i in range(x):
    for j in range(y):
        matrix[i][j] = integer_list.pop(np.random.randint(0, len(integer_list)))

Edit: I wasn't able to get it working with random choice. When I use random choice it returns a single value, rather than a list of values. A more efficient solution would be to simply shuffle the list.

import numpy as np
import random
# define values 
n = 0
m = 20 
x = 3
y = 4 

integer_list = [i for i in range(n, m)]  # assuming m is exclusive
random.shuffle(integer_list)
matrix = np.zeros((x,y))
for i in range(x):
    for j in range(y):
        matrix[i][j] = integer_list.pop()

Upvotes: 0

kaptankusto
kaptankusto

Reputation: 77

You could use np.random.choice.

np.random.choice(5, 3, replace=False)
# Output:
array([3,1,0]) # random

Upvotes: 1

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