CODEWITHSUNDEEP
python
SA13
SA13

Reputation: 33

cannot unpack non-iterable int object. BMI Calculator

I am trying to print out the number of people in each category of my BMI calculator. Receiving error: > overweight, underweight, normal, obese = 0 TypeError: cannot unpack non-iterable int object

recipients = ["John", "Dee", "Aleister", "Lilith", "Paul", "Reggy"]
BMI_calc = []


def BMI(weights, heights):
    bmi_total = (weights * 703) / (heights ** 2)
    return bmi_total


def check(BMI):
  if BMI <= 18.5:
    print("Your underweight.")

  elif BMI > 18.5 and BMI < 24.9:
    print("You're normal weight.")

  elif BMI > 25 and BMI < 29.9:
    print("You're overweight.")

  elif BMI > 30:
    print("You're obese.")


for recipient in recipients:
    heights_ = int(input("What is your height " + recipient + "  :" ))
    weights_ = int(input("What is your weight " + recipient + "  :" ))
    BMI_info={"name":recipient,"weight":weights_,"height":heights_,"BMI":BMI(weights_, heights_)}
    BMI(BMI_info["weight"],BMI_info["height"])
    BMI_calc.append(BMI_info)



for person_info in BMI_calc:
    print(person_info["name"],end="\t")
    check(person_info["BMI"])


overweight, underweight, normal, obese = 0

def check(BMI):
  if BMI <= 18.5:
    print("Your underweight.")
    underweight += 1
  elif BMI > 18.5 and BMI < 24.9:
    print("You're normal weight.")
    normal += 1

  elif BMI > 25 and BMI < 29.9:
    print("You're overweight.")
    overweight +=1

  elif BMI > 30:
    print("You're obese.")
    obese += 1

print("This many people are" ,underweight)

I am trying to print out "This many people are underweight with the value of individuals it that category same for over, normal and obese.

Upvotes: 0

Views: 116

Answers (2)

sedavidw
sedavidw

Reputation: 11741

Your error tells you what is going wrong. It's on the following line

overweight, underweight, normal, obese = 0

What that line tries to do is "unpack" (or separate) out the right side of the equal sign and put it into each of the four variables on the left. 0 cannot be broken part, it's not a tuple

If you want to initialize each variable to 0 simply do each on a different line.

Or you could assign them to a tuple that it's separated out

overweight, underweight, normal, obese = (0, 0, 0, 0)

But this seems like overkill and less readable IMO

UPDATE

Per comment below, since ints are immutable you can do the following

overweight = underweight = normal = obese = 0

Upvotes: 1

SMMousaviSP
SMMousaviSP

Reputation: 816

This problem is you're trying to assign a value to 4 different variables in one line, and python expects you to give a tuple containing 4 different values, not one; it doesn't broadcast your one value to 4 different variables.

You have 2 option, you can set the value of your variables to 0 in a different line like this:

overweight = 0
underweight = 0
normal = 0
obese = 0

Or you can do it in one line, but instead of only one 0, you should give a tuple containing four 0, like this:

overweight, underweight, normal, obese = (0, 0, 0, 0)

Upvotes: 1

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