Reputation: 20444
Outputting from a directions api I have a duration it will take the user to get from a to b. At the moment it is minutes but if the users journey will take 3 hours and 20 minutes it will output 200 minutes.
I would like it to work out that that is greater than 60 minutes. then divide by 60 and add the remainder to give
3 hours 20 minutes.
How do we do this.
Marvellous
Upvotes: 13
Views: 24772
Reputation: 3583
In case you have duration in seconds, you can format it with PHP gmdate()
function:
echo gmdate("H:i:s", $seconds);
(Note: works for durations up to 24 hours)
Upvotes: 10
Reputation: 8135
For those who need it... Minutes to Period of Time - PT:
<?php
function pttime($time, $format)
{
if ($time < 1) {
return;
}
$hours = floor($time / 60);
$minutes = ($time % 60);
//is PT
if ($format == 'PT') {
//full hour
if (($hours > 0) && ($minutes == 0)) {
$time_result = 'PT' . $hours . 'H';
}
//hour and minutes
if (($hours > 0) && ($minutes <> 0)) {
$time_result = 'PT' . $hours . 'H' . $minutes . 'M';
}
//just minutes
if ($hours == 0) {
$time_result = 'PT' . $minutes . 'M';
}
}
//it's not PT
else {
$time_result = sprintf("%02s", $hours) . ':' . sprintf("%02s", $minutes);
}
return $time_result;
}
//input in minutes and its outputs
echo pttime(155,'PT'); //output -> PT2H35M
echo pttime(52,'PT'); //output -> PT52M
echo pttime(60,'PT'); //output -> PT1H
echo pttime(60,''); //output -> 01:00
Upvotes: 0
Reputation: 1971
with php >= 5.3.0 you could do that :
$dt = new DateTime();
$dt->add(new DateInterval('PT200M'));
$interval = $dt->diff(new DateTime());
echo $interval->format('%Hh %Im %Ss');
Output (on my locale) : 02h 40m 00s
source : http://php.net/manual/en/class.dateinterval.php
Upvotes: 24
Reputation: 49
Thanks for the function. I needed to change it to make it work better: The minutes were over 60:
$seconds = $secs % 60;
$hours = floor($secs / 3600);
$secs = $secs - $hours*3600;
$minutes = floor($secs / 60);
Best
Upvotes: 0
Reputation: 31
A simple duration-to-formatted-time example (with the duration given in seconds, and the output formatted as [##:]##:##):
public function format_duration($secs, $delimiter = ':')
{
$seconds = $secs % 60;
$minutes = floor($secs / 60);
$hours = floor($secs / 3600);
$seconds = str_pad($seconds, 2, "0", STR_PAD_LEFT);
$minutes = str_pad($minutes, 2, "0", STR_PAD_LEFT).$delimiter;
$hours = ($hours > 0) ? str_pad($hours, 2, "0", STR_PAD_LEFT).$delimiter : '';
return "$hours$minutes$seconds";
}
Upvotes: -2
Reputation: 5504
function getNiceDuration($durationInSeconds) {
$duration = '';
$days = floor($durationInSeconds / 86400);
$durationInSeconds -= $days * 86400;
$hours = floor($durationInSeconds / 3600);
$durationInSeconds -= $hours * 3600;
$minutes = floor($durationInSeconds / 60);
$seconds = $durationInSeconds - $minutes * 60;
if($days > 0) {
$duration .= $days . ' days';
}
if($hours > 0) {
$duration .= ' ' . $hours . ' hours';
}
if($minutes > 0) {
$duration .= ' ' . $minutes . ' minutes';
}
if($seconds > 0) {
$duration .= ' ' . $seconds . ' seconds';
}
return $duration;
}
Upvotes: 13
Reputation: 16455
function format_minutes($value)
{
$hours = intval($value / 60);
$minutes = $value % 60;
if ($hours != 0) {
$str = $hours . ' hour';
// Handle pluralisation.
if (abs($hours) != 1) {
$str .= 's';
}
}
// Always show minutes if there are no hours.
if ($minutes != 0 || $hours == 0) {
$str .= ' ' . $minutes . ' minute';
// Handle pluralisation.
if (abs($minutes) != 1) {
$str .= 's';
}
}
// There will be a leading space if hours is zero.
return trim($str);
}
Upvotes: 0
Reputation: 2140
<?php
$time = 200; // minutes
if ($time > 60) {
$minutes = $time % 60;
$hours = ($time - $minutes) / 60;
}
echo "$hours hours $minutes minutes";
?>
Use modulo division :)
Upvotes: 1
Reputation: 22972
$minutes = 200;
if ($minutes >= 60)
{
$hours = (int)($minutes / 60);
$minutes = $minutes % 60;
}
Upvotes: 3