CODEWITHSUNDEEP
rustserdehyper
Mike Marcacci
Mike Marcacci

Reputation: 1961

Deserialize map of remote structs using serde_json

I have a use case that requires deserializing JSON into a map of "remote" (defined in another crate) structs. I've had a laughably difficult time with this, so I must be missing something obvious.

The following is essentially the desired end state:

use hyper::Uri;
use serde_json;
use std::collections::HashMap;

fn main() {
    let data = r#"
        {
            "/a": "http://example.com/86f7e437faa5a7fce15d1ddcb9eaeaea377667b8",
            "/b": "http://example.com/e9d71f5ee7c92d6dc9e92ffdad17b8bd49418f98",
            "/c": "http://example.com/84a516841ba77a5b4648de2cd0dfcb30ea46dbb4"
        }"#;

    let map: HashMap<String, Uri> = serde_json::from_str(data).unwrap();

    println!("{:?}", map);
}

which fails because:

the trait bound `Uri: serde::de::Deserialize<'_>` is not satisfied required because of the requirements
on the impl of `serde::de::Deserialize<'_>` for `HashMap<std::string::String, Uri>`

While the serde docs describe a pretty nasty but potentially viable workaround for deriving Deserialize on remote structs, it requires the use of #[serde(with = "LocalStructRedefinition")] on any referencing container type, which does not appear possible when creating a HashMap.

Intuitively this must be a common use case... is there a way to solve this that doesn't involve:

  1. deserializing the data into a HashMap<String, String>
  2. iterate through the map, parsing the values into a new HashMap<String, Uri>

Upvotes: 2

Views: 3672

Answers (2)

jonasbb
jonasbb

Reputation: 2613

By using the serde_with crate most of the deserialization logic can be reduced to an attribute. It has the advantage of avoiding any wrapper types except for deserialization.

#[serde_with::serde_as]
#[derive(serde::Deserialize)]
struct Wrapper(
    #[serde_as(as = "HashMap<_, serde_with::DisplayFromStr>")]
    HashMap<String, hyper::Uri>
);

fn main() {
    let data = r#"
        {
            "/a": "http://example.com/86f7e437faa5a7fce15d1ddcb9eaeaea377667b8",
            "/b": "http://example.com/e9d71f5ee7c92d6dc9e92ffdad17b8bd49418f98",
            "/c": "http://example.com/84a516841ba77a5b4648de2cd0dfcb30ea46dbb4"
        }"#;

    let map: Wrapper = serde_json::from_str(data).unwrap();
    println!("{:?}", map.0);
}

Upvotes: 1

Njuguna Mureithi
Njuguna Mureithi

Reputation: 3866

With a mix of Into, deserialize_with and flatten, you can achieve what you want:

use serde_json;
use std::collections::HashMap;
use hyper::Uri;
use serde::{de::Error, Deserialize, Deserializer};

#[derive(Debug, Deserialize)]
struct MyUri(#[serde(deserialize_with = "from_uri")] Uri);

#[derive(Debug, Deserialize)]
struct MyUriMap {
    #[serde(flatten)]
    inner: HashMap<String, MyUri>
}

impl Into<HashMap<String, Uri>> for MyUriMap {
    fn into(self) -> HashMap<String, Uri> {
        self.inner.into_iter().map(|x| (x.0, x.1.0)).collect()
    }
}


fn from_uri<'de, D>(deserializer: D) -> Result<Uri, D::Error>
where
    D: Deserializer<'de>,
{
    let s: &str = Deserialize::deserialize(deserializer)?;
    s.parse().map_err(D::Error::custom)
}


fn main() {
    let data = r#"
        {
            "/a": "http://example.com/86f7e437faa5a7fce15d1ddcb9eaeaea377667b8",
            "/b": "http://example.com/e9d71f5ee7c92d6dc9e92ffdad17b8bd49418f98",
            "/c": "http://example.com/84a516841ba77a5b4648de2cd0dfcb30ea46dbb4"
        }"#;

    let map: MyUriMap = serde_json::from_str(data).unwrap();

    // let map: HashMap<String, Uri> = map.into();
    // I think to get HashMap<String, Uri> you have to do an iter as seen in the Into implementation
    println!("{:?}", map);
}

See in Playground

PS. In my answer, to get HashMap<String, Uri> you have to do an iter as seen in the Into implementation

Upvotes: 4

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