How to match one word only within double quotes

Question

I was trying to match one word within double quotes but not outside. For instance:

"xxxxxxxxxxxxxx " , OneWord ; OneWord, "xxxxx , OneWord xxxxx". " OneWord 1" ----  " OneWord 2":

The expected match I need is
"xxxxx , OneWord xxxxx"
" OneWord 1"
" OneWord 2"

I had tried this

"(?:(?!OneWord)[^"])*(?(?=")\"\K|OneWord[^"]*")

Finally, I realized that the quotes not containing the OneWord match and it's just not showed. ex:"xxxxxxxxxxxxxx ". it matches but not showed. What I need is just to have the quotes containing the OneWord matched.

Is that possible?

Answer 1

You could use

"[^"]*\bOneWord\b[^"]*"(?=(?:[^"]*"[^"]*")*[^"]*$)

Explanation

• "[^"]* Match " followed by 0+ occurrences of any char except "
• \bOneWord\b Match OneWord between word boundaries
• [^"]*" Match 0+ occurrences of any char except ", then match "
• (?= Positive lookahead, assert what is at the right
  • (?:[^"]*"[^"]*")* Optionally match pairs of double quotes
  • [^"]*$ Match an optional trailing part without " till the end of the string
• ) Close lookahead

Regex demo

Or a bit longer version accepting an escaped double quote

Regex demo