CODEWITHSUNDEEP
c++timec++-chrono
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Reputation: 171

converting std::chrono::steady_clock::time_point to long double

How can I convert std::chrono::steady_clock::time_point to a double after calculating the change in time.

int main()
{
    std::chrono::steady_clock::time_point start, finish;
   
    start = std::chrono::steady_clock::now();
    finish = start;

    while (true){
        long double elapsedTime = std::chrono::duration_cast<std::chrono::nanoseconds>(finish -  start).count() / 1000000000;

        std::cout << "Time elapsed (in seconds), " << elapsedTime << std::endl;
    }
    



    return 0;
}

Edit: it works, but it only returns 0 or 1, what im looking for is like 1.13715263724 or something

Upvotes: 0

Views: 928

Answers (1)

Vroomy
Vroomy

Reputation: 21

First, you should update start at the begin of the loop, and finish at the end. And to get a floating value, 1000000000 have to be replaced by 1000000000.0 :

while (1) {
    start = std::chrono::steady_clock::now();
    long double elapsedTime = std::chrono::duration_cast<std::chrono::nanoseconds>(start -  finish).count() / 1000000000.0;
    std::cout << "Time elapsed (in seconds), " << elapsedTime << std::endl;
    finish = start;
}

Upvotes: 1

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