Reputation: 337
I have below code snippet
seta = ["apple","orange","grapes","mango", "starfruit"]
setb = ["papaya","mango","jackfruit","grapes","lychee"]
def setOperation(seta, setb):
union = set(seta) | set(setb)
print(list(union))
intersection = set(seta) & set(setb)
print(list(intersection))
difference = set(seta) - set(setb)
print(list(difference))
difference = set(setb) - set(seta)
print(list(difference))
sdifference = set(seta) ^ set(setb)
print(list(sdifference))
print(list(frozenset(set(seta))))
setOperation(seta,setb)
which produces different different output everytime I run it. Like -
['jackfruit', 'apple', 'mango', 'starfruit', 'grapes', 'lychee', 'orange', 'papaya']
['grapes', 'mango']
['orange', 'apple', 'starfruit']
['jackfruit', 'papaya', 'lychee']
['jackfruit', 'apple', 'starfruit', 'lychee', 'papaya', 'orange']
['orange', 'apple', 'grapes', 'mango', 'starfruit']
and
['grapes', 'mango', 'apple', 'orange', 'starfruit', 'lychee', 'papaya', 'jackfruit']
['grapes', 'mango']
['starfruit', 'apple', 'orange']
['lychee', 'papaya', 'jackfruit']
['apple', 'orange', 'starfruit', 'lychee', 'papaya', 'jackfruit']
['grapes', 'starfruit', 'mango', 'apple', 'orange']
but I want the output as below -
['apple', 'grapes', 'jackfruit', 'lychee', 'mango', 'orange', 'papaya', 'starfruit']
['grapes', 'mango']
['apple', 'orange', 'starfruit']
['jackfruit', 'lychee', 'papaya']
['apple', 'jackfruit', 'lychee', 'orange', 'papaya', 'starfruit']
Due to this change of order I am failing one code competition exam again. Please do let me know if I missed something simple or did anything stupid. I want the output in lexicographical order. TIA
Upvotes: 0
Views: 945
Reputation: 10624
Set is an unordered data structure in Python. Given that you want the output in lexicographical order, just add 'sorted()' inside print commands:
seta = ["apple","orange","grapes","mango", "starfruit"]
setb = ["papaya","mango","jackfruit","grapes","lychee"]
def setOperation(seta, setb):
union = set(seta) | set(setb)
print(sorted(union))
intersection = set(seta) & set(setb)
print(sorted(intersection))
difference = set(seta) - set(setb)
print(sorted(difference))
difference = set(setb) - set(seta)
print(sorted(difference))
sdifference = set(seta) ^ set(setb)
print(sorted(sdifference))
print(sorted(frozenset(set(seta))))
setOperation(seta,setb)
Output:
['apple', 'grapes', 'jackfruit', 'lychee', 'mango', 'orange', 'papaya', 'starfruit']
['grapes', 'mango']
['apple', 'orange', 'starfruit']
['jackfruit', 'lychee', 'papaya']
['apple', 'jackfruit', 'lychee', 'orange', 'papaya', 'starfruit']
['apple', 'grapes', 'mango', 'orange', 'starfruit']
Upvotes: 1
Reputation: 1710
Sets are unordered so you can't expect to get a consistent order. Since your expected output is in sorted order, you can simply view the sorted union/intersection etc like so:
seta = set(["apple","orange","grapes","mango", "starfruit"])
setb = set(["papaya","mango","jackfruit","grapes","lychee"])
print(sorted(seta | setb)) # Union
print(sorted(seta & setb)) # Intersection
# ... etc ...
Upvotes: 2