CODEWITHSUNDEEP
cfunctionscanf
user14512537
user14512537

Reputation:

unexpected output -scanf and function check

So i am trying to write this program but i get 10 no matter what the input is. My function seems correct to me so is it a scanf issue?

Write a program to input 10 integers and decide how many of them satisfy the following rule: abcd = (ab + cd)2 e.g. 3025=(30+25) Use a function that receives an integer parameter returns 1 if it satisfies the above rule, returns 0 otherwise.

int check(int n);
int main(void)
{
    int n, i, j = 0;
    printf("Input 10 integers: ");
    for (i = 0; i < 10; i++)
    {
        scanf("%d", &n);
        if (check(n) == 1)
        {
            j++;
        }
    }
    printf("%d\n", j);
}
int check(int x)
{
    if (((x / 100) + (x % 100)) * ((x / 100) + (x % 100))) 
    {
        return 1;
    }
    else
    {
        return 0;
    }
}

Upvotes: 0

Views: 51

Answers (1)

CS Pei
CS Pei

Reputation: 11047

The issue I think is the check function,

if (((x / 100) + (x % 100)) * ((x / 100) + (x % 100)))  // <---- anything not zero will be true
{
    return 1;
}

The expression inside if will convert any integer which is not zero to true. The expression as it is written is if (x * x) which only false if x == 0.

Upvotes: 1

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