CODEWITHSUNDEEP
javascriptarraysjsonsorting
DjBillje Official
DjBillje Official

Reputation: 386

JavaScript how to find data of array of object without giving exact search value that matches with value of object

How to make a function that finds data of array of object without giving exact search value that matches with value of object.

For example my array is :

const array = 
[{
    "name": "Max Messi",
    "age": 21,
    "gender": "male"
},
{
    "name": "tina baidya",
    "age": 10,
    "gender": "female"
},
{
    "name": "tina shrestha",
    "age": 100,
    "gender": "female"
}
]

Now i want a function to return all the data that has name "tina" in it.

I tried using array.filter() method but it requires exact search name. Like i need to type tina shrestha instead of just tina

this is what I had tried:

const array = 
[{
    "name": "Max Messi",
    "age": 21,
    "gender": "male"
},
{
    "name": "Lina baidya",
    "age": 10,
    "gender": "female"
},
{
    "name": "tina shrestha",
    "age": 100,
    "gender": "female"
}
]
function findData(data, id){
    const found = data.filter(element => element.name === id)
    return found
}
console.log(findData(array, "tina"))//logs empty array as i need to type full search value

So how can i make the function that searches json data without putting exact value.

Upvotes: 2

Views: 735

Answers (2)

Manuel Abascal
Manuel Abascal

Reputation: 6380

You can try using the includes() method like so:

const array = [
    {
        "name": "Max Messi",
        "age": 21,
        "gender": "male"
    },
    {
        "name": "Lina baidya",
        "age": 10,
        "gender": "female"
    },
    {
        "name": "tina shrestha",
        "age": 100,
        "gender": "female"
    }
]

const findData = (data, searchParam) => {
    return data.filter(element => element.name.includes(searchParam.toLowerCase()));
}

const results = findData(array, "tin");

console.log(results);

However, it won't work if you search for example tina2 or tinathy so it doesn't cover all edge-cases!

Upvotes: 1

Nicholas Tower
Nicholas Tower

Reputation: 85132

You're almost there, you just need to check if the name includes your string, rather than being equal to it:

const found = data.filter(element => element.name.includes(id))

Upvotes: 4

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