Reputation: 1939
I have a dictionary like so:
d = {'3a0fe308-b78d-4080-a68b-84fdcbf5411e': 'SUCCEEDED-HALL-IC_GBI', '7c975c26-f9fc-4579-822d-a1042b82cb17': 'SUCCEEDED-AEN-IC_GBI', '9ff20206-a841-4dbf-a736-a35fcec604f3': 'SUCCEEDED-ESP2-IC_GBI'}
I would like to convert my dictionary into something like this to make a dataframe where I put all the keys and values in a separate list.
d = {'key': ['3a0fe308-b78d-4080-a68b-84fdcbf5411e', '7c975c26-f9fc-4579-822d-a1042b82cb17', '9ff20206-a841-4dbf-a736-a35fcec604f3'],
'value': ['SUCCEEDED-HALL-IC_GBI', 'SUCCEEDED-AEN-IC_GBI', 'SUCCEEDED-ESP2-IC_GBI']
What would be the best way to go about this?
Upvotes: 1
Views: 612
Reputation: 19
You can create the dataframe zipping the key/value lists with zip function:
import pandas as pd
df = pd.DataFrame(list(zip(d.keys(),d.values())), columns=['key','value'])
Upvotes: 1
Reputation: 66
You can easily create a DataFrame like this:
import pandas as pd
d = {'3a0fe308-b78d-4080-a68b-84fdcbf5411e': 'SUCCEEDED-HALL-IC_GBI',
'7c975c26-f9fc-4579-822d-a1042b82cb17': 'SUCCEEDED-AEN-IC_GBI',
'9ff20206-a841-4dbf-a736-a35fcec604f3': 'SUCCEEDED-ESP2-IC_GBI'}
table = pd.DataFrame(d.items(), columns=['key', 'value'])
If you just want to rearrange your Dictionary you could do this:
d2 = {'key': list(d.keys()), 'value': list(d.values())}
Upvotes: 3
Reputation: 150735
Since you tagged pandas
, try:
pd.Series(d).reset_index(name='value').to_dict('list')
Output:
{'index': ['3a0fe308-b78d-4080-a68b-84fdcbf5411e',
'7c975c26-f9fc-4579-822d-a1042b82cb17',
'9ff20206-a841-4dbf-a736-a35fcec604f3'],
'value': ['SUCCEEDED-HALL-IC_GBI',
'SUCCEEDED-AEN-IC_GBI',
'SUCCEEDED-ESP2-IC_GBI']}
Pure python:
{'key':list(d.keys()), 'value': list(d.values())}
output:
{'key': ['3a0fe308-b78d-4080-a68b-84fdcbf5411e',
'7c975c26-f9fc-4579-822d-a1042b82cb17',
'9ff20206-a841-4dbf-a736-a35fcec604f3'],
'value': ['SUCCEEDED-HALL-IC_GBI',
'SUCCEEDED-AEN-IC_GBI',
'SUCCEEDED-ESP2-IC_GBI']}
Upvotes: 1