CODEWITHSUNDEEP
swiftmacos
Adam M.
Adam M.

Reputation: 105

How to show cursor in NSTextView click location - MacOS

I am working on a macOS application. I want to write a code that shows the cursor on the click location in NSTextView. So I searched in StackOverFlow and found the following code for iOS:

@objc func didTapTextView(recognizer: UITapGestureRecognizer) {
    
    if recognizer.state == .ended {
        textView.isEditable = true
        textView.becomeFirstResponder()

        let location = recognizer.location(in: textView)
        if let position = textView.closestPosition(to: location) {
            let uiTextRange = textView.textRange(from: position, to: position)

            if let start = uiTextRange?.start, let end = uiTextRange?.end {
                let loc = textView.offset(from: textView.beginningOfDocument, to: position)
                let length = textView.offset(from: start, to: end)

                textView.selectedRange = NSMakeRange(loc, length)
            }
        }
    }
}

So, to convert the code from iOS to macOS, I can:

The problem is:

I can't convert the methods .closestPosition, .textRange and .offset to macOS, because they are only available in UIKit, and they return UIKit values like UITextPosition and UITextRange.

Minimal Reproducible Example

To reproduce the problem, just create a document-based Cocoa app (macOS), and add a Scrollable TextView, then the code will be:

import Cocoa

class ViewController: NSViewController, NSGestureRecognizerDelegate {

    @IBOutlet var textView: NSTextView!

    override func viewDidLoad() {
        super.viewDidLoad()
                
        // Set tap gesture
        let singleClickGesture = NSClickGestureRecognizer(target: self, action: #selector(singleClickGesture(_:)))
        singleClickGesture.numberOfClicksRequired = 1 // single
        singleClickGesture.delegate = self
        textView.addGestureRecognizer(singleClickGesture)
        // create attributed string
        let myAttrString = NSMutableAttributedString(string: "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.")
        // Write it to the Text View
        textView.textStorage?.append(myAttrString)
    }
    
    @objc func singleClickGesture(_ recognizer: NSClickGestureRecognizer) {
        // Show cursor and set it to position on tapping
        if recognizer.state == .ended {
            textView.isEditable = true
            textView.window?.makeFirstResponder(textView)

        // Comment the next 9 lines to see the problem.
        // TextView is not responding correctly to mouse clicks.
        // The next lines fixes the problem for UIKit (iOS),
        // but I couldn't make equivalent code for Cocoa (macOS).
            let location = recognizer.location(in: textView)
            if let position = textView.closestPosition(to: location) {
                let uiTextRange = textView.textRange(from: position, to: position)
                if let start = uiTextRange?.start, let end = uiTextRange?.end {
                    let loc = textView.offset(from: textView.beginningOfDocument, to: position)
                    let length = textView.offset(from: start, to: end)
                    textView.selectedRange = NSMakeRange(loc, length)
                }
            }
        }
    }

}

Solutions?

Upvotes: 2

Views: 670

Answers (1)

Willeke
Willeke

Reputation: 15633

Here you go:

@objc func singleClickGesture(_ recognizer: NSClickGestureRecognizer) {
    // Show cursor and set it to position on tapping
    print("click \(String(describing: NSApp.currentEvent))")
    if recognizer.state == .ended {
        textView.isEditable = true
        if let window = textView.window, window.makeFirstResponder(textView) {
            let location = recognizer.location(in: textView)
            let position = textView.characterIndexForInsertion(at: location)
            textView.selectedRange = NSMakeRange(position, 0)
        }
    }
}

Upvotes: 1

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