Reputation: 616
I am trying to replicate ajax request from a web page (https://droughtmonitor.unl.edu/Data/DataTables.aspx). AJAX is initiated when we select values from dropdowns.
I am using the following request using python, but not able to see the response as in Network tab of the browser.
import bs4
import requests
import lxml
ses = requests.Session()
ses.get('https://droughtmonitor.unl.edu/Data/DataTables.aspx')
headers_dict = {'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36'
}
url = 'https://droughtmonitor.unl.edu/Ajax2018.aspx/ReturnTabularDMAreaPercent_urban'
req_data = {'area':'00064', 'statstype':'1'}
resp = ses.post(url,data = req_data,headers = headers_dict)
soup = bs4.BeautifulSoup(resp.content,'lxml')
print(soup)
Upvotes: 1
Views: 88
Reputation: 3010
From the requests documentation:
Instead of encoding the dict yourself, you can also pass it directly using the json parameter (added in version 2.4.2) and it will be encoded automatically:
>>> url = 'https://api.github.com/some/endpoint'
>>> payload = {'some': 'data'}
>>> r = requests.post(url, json=payload)
Then, to get the output, call r.json()
and you will get the data you are looking for.
Upvotes: 2
Reputation: 2439
You need to add several things to your request to get an Answer from the server.
dict
to json
to pass it as string and not as dict
.request-data
by setting the request header to Content-Type:application/json; charset=utf-8
with those changes I was able to request the correkt data.
import bs4
import requests
ses = requests.Session()
ses.get('https://droughtmonitor.unl.edu/Data/DataTables.aspx')
headers_dict = {'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36',
'Content-Type': 'application/json; charset=utf-8'}
url = 'https://droughtmonitor.unl.edu/Ajax2018.aspx/ReturnTabularDMAreaPercent_urban'
req_data = json.dumps({'area':'00037', 'statstype':'1'})
resp = ses.post(url,data = req_data,headers = headers_dict)
soup = bs4.BeautifulSoup(resp.content,'lxml')
print(soup)
Quite a tricky problem I must say.
Upvotes: 2