Reputation: 81

How to convert numbers into text?

I have been learning Objective-C with the Kochan book and I can't figure out how to do this exercise program. Only odd numbered exercises are listed online and this one is even. The exercise is to convert numbers into words. So, if "932" was entered, the program should return: "nine three two"

I used a do, while loop but the words came out backwards, as in "two three nine". Can anyone suggest a technique that works for this?

int number, digit;


NSLog(@"Type in your integer.");
scanf("%i", &number);


 do
 {
     digit = number % 10;

     if (digit == 0)
         NSLog(@"zero");
     if (digit == 1)
         NSLog(@"one");
     if (digit == 2)
         NSLog(@"two");
     if (digit == 3)
         NSLog(@"three");
     if (digit == 4)
         NSLog(@"four");
     if (digit == 5)
         NSLog(@"five");
     if (digit == 6)
         NSLog(@"six");
     if (digit == 7)
         NSLog(@"seven");
     if (digit == 8)
         NSLog(@"eight");
     if (digit == 9)
         NSLog(@"nine");

     number /= 10;
 }
while (number != 0);

Upvotes: 8

Answers (8)

Ajjjjjjjj

Reputation: 675

very easy, there are number of approaches but i normally try this :

  do
    {
         digit = number % 10;
        switch (digit) {
            case 0:
                [self prependNumber:@"zero"];
                break;
            case 1:
                [self prependNumber:@"one"];
                break;
            case 2:
                [self prependNumber:@"two"];
                break;
            case 3:
                [self prependNumber:@"three"];
                break;
            case 4:
                [self prependNumber:@"four"];
                break;
            case 5:
                [self prependNumber:@"five"];
                break;
            case 6:
                [self prependNumber:@"six"];
                break;
            case 7:
                [self prependNumber:@"seven"];
                break;
            case 8:
                [self prependNumber:@"eight"];
                break;
            case 9:
                [self prependNumber:@"nine"];
                break;
            default:
                break;
        }


        number /= 10;
    }
    while (number != 0);

/************/
-(void) prependNumber:(NSString*)str{
 NSLog(str);
}

Upvotes: 0

Ratnesh

Reputation: 1

I use nested under nested loop but believe that this works

    int i, j, number, reversenumber = 0;

    NSLog(@" Input Number:");
    scanf( "%i", &number);

    if (number != 0)
        // chekcing for zero entry
    {
        for (;number!= 0; number = number/10)
            //for reversing the number entered so that the words doesn't come reversed when printed
        {
            i = number%10;
            reversenumber = reversenumber * 10 + i;
        }

        NSLog(@"Reverser Number for the input number is %i", reversenumber);
        // mid routine check to print the reversed number

        while(reversenumber != 0)
        {
            j = reversenumber % 10;
            switch (j)
            {
                case 9:
                    NSLog(@"nine");
                    break;
                case 8:
                    NSLog(@"eight");
                    break;
                case 7:
                    NSLog(@"seven");
                    break;
                case 6:
                    NSLog(@"six");
                    break;
                case 5:
                    NSLog(@"five");
                    break;
                case 4:
                    NSLog(@"four");
                    break;
                case 3:
                    NSLog(@"three");
                    break;
                case 2:
                    NSLog(@"two");
                    break;
                case 1:
                    NSLog(@"one");
                    break;
                default:
                    NSLog(@"zero");
            }
            reversenumber /= 10;
        }

    }
    else
        NSLog(@"Zero");
}

    return 0;

}

Upvotes: 0

Francis

Reputation: 31

#import <Foundation/Foundation.h>

int main(int argc, const char * argv[])
{

@autoreleasepool {

    // insert code here...
    int number;     //store the value the user enter
    int lastDigit;  //pick of the last digit of the integer
    int tempNum;    //a temporary storage of the integer the user enter
    int count = 0;  //used to count how many digits were entered
    int count2;     //going to be use as a duplicate of count



    NSLog(@"Enter an integer");
    scanf("%i", &number);
    tempNum = number;


    //Loop to find out how many digits were entered
    for (; number != 0; number /= 10) {
        count +=1;
        }

    //Loop to convert the numbers into words
    for (; count != 0; count -= 1) {
        count2 = count;     //set count2 to count so the for and while loop use them independently
        number = tempNum;   //restore the value entered by by the user to the number variable


        //Loop to reverse the order of the last digit

        while (count2 != 0) {           //loops to the same number of counts to get the first digit
            lastDigit = number % 10;    //picks off the last value in the integer
            number /= 10;               //enables the loop to set the last value of the integer to zero
            count2 -=1;                 //loops one less time to get the numbers from front to back

        }
        //switch statements
        switch (lastDigit) {
            case 9:
                NSLog(@"nine");
                break;
            case 8:
                NSLog(@"eight");
                break;
            case 7:
                NSLog(@"seven");
                break;
            case 6:
                NSLog(@"six");
                break;
            case 5:
                NSLog(@"five");
                break;
            case 4:
                NSLog(@"four");
                break;
            case 3:
                NSLog(@"three");
                break;
            case 2:
                NSLog(@"two");
                break;
            case 1:
                NSLog(@"one");
                break;
            case 0:
                NSLog(@"zero");
                break;
            default:
                break;
        }
    }
   }
return 0;
}

Upvotes: 0

JAL

Reputation: 3319

As a learning exercise, I modified Dave's code:

+(NSString*)doIt:(NSString*)inString delimiter:(NSString*)delimiter{
    NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
    [f setNumberStyle:NSNumberFormatterSpellOutStyle];
    NSMutableString* outString= [[NSMutableString alloc]init];
    for (int i=0; i< [inString length]; i++) {
        unsigned char oneChar= [inString characterAtIndex:i];
        if (oneChar>47 && oneChar<58) {
            NSString* temp=[f stringFromNumber:[NSNumber numberWithUnsignedChar:oneChar-48]];
            [outString appendFormat:@"%@",temp];
            [outString appendString:delimiter];
        }
    }
    [f release];
    [outString autorelease];
    return outString;
}

Upvotes: 1

Jeffrey Berthiaume

Reputation: 4594

Since you're adding the numbers to a string, and you want to calculate them right to left, prepend the string with each new number. Something like:

numberString = [NSString stringWithFormat:@"%@ %@", theNewNumber, numberString];

Where theNewNumber is a string (like @"six") and numberString is the string that you want to output once you're done...

(oh, and don't forget to initialize numberString before you start looping...something like:

NSString *numberString = @"";

=====

Based on the code you just posted, you could either do it mathematically, or just pre-pend a string like this:

Put this variable in your .h file:

NSString *numberString;

Then put this in your .m:

- (void) prependNumber:(NSString *)num {
  numberString = [NSString stringWithFormat:@"%@ %@", num, numberString];
}

NSLog(@"Type in your integer.");
scanf("%i", &number);
numberString = @"";


 do
 {
     digit = number % 10;

     if (digit == 0)
         [self prependNumber:@"zero"];
     if (digit == 1)
         [self prependNumber:@"one"];
     if (digit == 2)
         [self prependNumber:@"two"];
     if (digit == 3)
         [self prependNumber:@"three"];
     if (digit == 4)
         [self prependNumber:@"four"];
     if (digit == 5)
         [self prependNumber:@"five"];
     if (digit == 6)
         [self prependNumber:@"six"];
     if (digit == 7)
         [self prependNumber:@"seven"];
     if (digit == 8)
         [self prependNumber:@"eight"];
     if (digit == 9)
         [self prependNumber:@"nine"];

     number /= 10;
 }
while (number != 0);

NSLog (@"%@", numberString);

Upvotes: 5

Dave DeLong

Reputation: 243146

This isn't exactly what you want, but for your consideration:

NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterSpellOutStyle];

NSString *s = [f stringFromNumber:[NSNumber numberWithInt:932]];
NSLog(@"%@", s);
[f release];

This will log:

nine hundred and thirty-two

Again, it's not the "nine three two" you want, but it's also nice and short. :)

Upvotes: 12

George Johnston

Reputation: 32258

Well it sounds like you're halfway there if you were able to get the numbers to convert to words already, even if output backwards.

Assuming you're looping through your data, incrementing the index, just start at the character length of the number, decrementing your index backwards, reversing your output.

We can't help you much more without seeing your actual code. ;)

Upvotes: 2

PengOne

Reputation: 48398

#import <Foundation/Foundation.h>

int main (int argc, const char * argv[]) {
    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
    int a, b, number, logNum, nThNum;

    NSLog(@"Please enter a valid integer: ");
    scanf("%d", &number); // read input as a decimal integer

    if (!number) // if zero or something other than a number is entered output zero
        NSLog(@"Zero");
    else if (number < 0) { // convert negatives to something that can be used
        number = -number;
        NSLog(@"(negative)"); // but output negative first then continue as usual
    }

    logNum = (log10(number) + 1); // find how many digits there are in the number

    for (int j=0; j < logNum; j++) {// loop based on number of digits
        a = pow(10,logNum-j);
        b = pow(10,logNum-1-j);
        nThNum = (number % a) / b;// find the nth digit in a number, in our case 1st
        switch (nThNum) {// output current digit that was found
            case 0:
                NSLog(@"Zero");
                break;
            case 1:
                NSLog(@"One");
                break;
            case 2:
                NSLog(@"Two");
                break;
            case 3:
                NSLog(@"Three");
                break;
            case 4:
                NSLog(@"Four");
                break;
            case 5:
                NSLog(@"Five");
                break;
            case 6:
                NSLog(@"Six");
                break;
            case 7:
                NSLog(@"Seven");
                break;
            case 8:
                NSLog(@"Eight");
                break;
            case 9:
                NSLog(@"Nine");
                break;
            default:
                break;
        }
    }

    [pool drain];
    return 0;
}

Well, now that you've posted your code, your method will work great if you first reverse the number. So, you can just write a short routine to do that, then use your own code.

Upvotes: 2

How to convert numbers into text?

Answers (8)

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