CODEWITHSUNDEEP
pythonpython-3.xstringtuples
anik jha
anik jha

Reputation: 219

Find unique list of tuples irrespective of order inside tuple

Given input:

[('is','my','order'), ('my','order', 'is'), ('temp', 'ques'), ('ques','temp')]

Desired output:

[('is','my','order'), ('temp', 'ques')]

In the output, the order of the tuple or the order of the contents of tuple doesn't matter.

Upvotes: 4

Views: 1180

Answers (3)

user14209927
user14209927

Reputation: 

mytuples = [('one','two'), ('two','one)]
myset=set()
for x in mytuples:
    myset.update(x)

print(myset)
output {'two', 'one'}

this will give you a set of all the unique values in your dataset. maybe not helpful

so you may have to check each tuple against every other tuple with the same length assuming you want to keep the tuple structure

Upvotes: 0

Moinuddin Quadri
Moinuddin Quadri

Reputation: 48120

Because for you order doesn't matter, you can use set to achieve this:

>>> input_list = [('is','my','order'), ('my','order', 'is'), ('temp', 'ques'), ('ques','temp')]

>>> set(tuple(sorted(l)) for l in input_list)
set([('ques', 'temp'), ('is', 'my', 'order')])

Firstly sort the content of each nested tuple to ensure your set considers tuples with common items as same. Then I am type-casting it again to tuple because sorted returns list which are unhashable. Finally, set removes duplicate entries of your tuples.

Please refer "set" documentation for more details.

Upvotes: 5

Lukas Schmid
Lukas Schmid

Reputation: 1960

You can sort each of the sublists and then add them to a list, dropping all duplicates

output_list = []
for tup in map(sorted, tuple_list):
  if tup not in output_list:
    output_list.append(tup)
print(output_list)

Upvotes: 0

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