CODEWITHSUNDEEP
javascriptarraysobject
K. P.
K. P.

Reputation: 561

Filter array of objects where one object's array has at least one match with another array

I apologize in advance, couldn't come up with a better example for data.

So I have the array things, which currently just consists of objects that contain an id property and an array which just contains random things/words I could suddenly come up with, and other_things, with with some random words from things array.

let things=[
  {
    id: 1,
    names: ['car','door','chair']
  },
  {
    id: 2,
    names: ['cat','dog','door']
  },
  {
    id: 3,
    names: ['phone','mouse','cat']
  },
  {
    id: 4,
    names: ['building','desk','pen']
  },
  {
    id: 5,
    names: ['road','date','number']
  }
];

let other_things=['car','door','pen'];

What I'd like to achieve is to filter array things, and only get those objects/elements, where the names array contains at least one element from the other_things array.

In this example, only things[2] and things[4] have no matches with any words from other_things, so we don't need them.

I have already tried many things, like combining ES6 methods, like filter, every or map, tried using nested for loops, but nothing has worked out for me unfortunately.

Upvotes: 0

Views: 1285

Answers (1)

Nishant
Nishant

Reputation: 55866

let things=[
  {
    id: 1,
    names: ['car','door','chair']
  },
  {
    id: 2,
    names: ['cat','dog','door']
  },
  {
    id: 3,
    names: ['phone','mouse','cat']
  },
  {
    id: 4,
    names: ['building','desk','pen']
  },
  {
    id: 5,
    names: ['road','date','number']
  }
];

let other_things=['car','door','pen'];

console.log(things.filter(t => t.names.filter(n => other_things.includes(n)).length > 0))

Upvotes: 3

Related Questions