CODEWITHSUNDEEP
php
I-M-JM
I-M-JM

Reputation: 15950

remove only those keys that are not present in another array

I have 2 arrays

$arr1 = array(
  'a' => array(some values here),
  'b' => array(some more values here),
  'c' => array(some more and more values here)
);

and 

$arr2 = array('a','c');

You can see that $arr2 have 2 values (a,c)

I want to keep those keys in $arr1 whose values are present in $arr1 (maintaining key-value association), and want remove all other values that are not in $arr2

so, output will be

$arr1 = array(
  'a' => array(some values here),
  'c' => array(some more and more values here)
);

How can I achieve this?

Upvotes: 3

Views: 226

Answers (1)

Brad Mace
Brad Mace

Reputation: 27886

To rephrase a bit, you want to find the keys that are present in both arrays, and keep the values from the first array. This happens to be what array_intersect_key does:

$arr1 = array_intersect_key($arr1, $arr2)

Note: I haven't used this function very often; you might need to change your second array to something like:

$arr2 = array('a' => 1, 'c' => 1);

to ensure that they're treated as keys rather than values.

Incorporating deceze's tip, you could also do

$arr1 = array_intersect_key($arr1, array_flip($arr2))

which wouldn't require changing your second array.

Upvotes: 5

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