CODEWITHSUNDEEP
pythonpython-3.xfunction
KAVAY SHARMA_ITSMEKAV
KAVAY SHARMA_ITSMEKAV

Reputation: 39

How to solve PyLint error: Invalid Syntax when my syntax is all correct

I am making a python function that gets a parameter of a character and then prints if the character is a uppercase, lowercase, a number or a special character. I get this error from Pylint

invalid syntax (, line 529)pylint(syntax-error)

#Finding if a number is a lowercase, uppercase, number or a special character
def check(charcater):
    character_ascii = ord(character)
    if character_ascii >= 97 and <= 122:
        print('The character',character,'is a lowercase letter')
    elif character_ascii >= 65 and <= 90:
        print('The character',character,'is a uppercase letter')
    elif character_ascii >= 48 and <= 57:
        print('The character',character,'is a number')
    else :
        print('The character',character,'is a special character')

I get the error here

if character_ascii >= 97 and <= 122:
                              ^

Please help me solve this error. Thanks in advance

Upvotes: 1

Views: 225

Answers (2)

chepner
chepner

Reputation: 532268

You have two separate comparison expressions, joined by and, and each one requires two operands.

if character_ascii >= 97 and character_ascii <= 122:

However, comparison operators allow for chaining, which allows you to include multiple comparisons in a single expression. The above is equivalent to

if 97 <= character_ascii <= 122:

In general, x op1 y op2 z is equivalent to x op1 y and y op2 z for any two comparison operators op1 and op2. Comparison operators are

  • <, >, <=, >=
  • ==, !=
  • is, is not
  • in not in

Upvotes: 1

Hadrian
Hadrian

Reputation: 937

comparison operators need a value on both sides so try changing them to this:

def check(charcater):
    character_ascii = ord(character)
    if character_ascii >= 97 and character_ascii <= 122:
        print('The character',character,'is a lowercase letter')
    elif character_ascii >= 65 and character_ascii <= 90:
        print('The character',character,'is a uppercase letter')
    elif character_ascii >= 48 and character_ascii <= 57:
        print('The character',character,'is a number')
    else :
        print('The character',character,'is a special character')

Upvotes: 0

Related Questions