CODEWITHSUNDEEP
pythonseleniumselenium-webdriverxpathwebdriverwait
Martin González
Martin González

Reputation: 11

Find span with selenium

I'm starting to programe in Python but i have a little problem. I want to click in this part. But when i run the program , it results that has a problem.

1

for driver.find_elements_by_xpath(//span[@class='link-indicator'][contains(text(),'View IP Detail')])
.click()

I write this code but my program doesn't run

Somebody can help me please.

Upvotes: 1

Views: 289

Answers (1)

undetected Selenium
undetected Selenium

Reputation: 193088

To click on the element with text as View IP Detail you can use either of the following Locator Strategies:

  • Using xpath and the textContext:

    driver.find_element_by_xpath("//span[@class='link-indicator'][contains(.,'View IP Detail')]").click()

  • Using xpath and the textContext of preceding element:

    driver.find_element_by_xpath("//span[contains(.,'ISP')]//following::span[@class='link-indicator'][contains(.,'View IP Detail')]").click()

Ideally, to click on the element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:

  • Using XPATH and the textContext:

    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//span[@class='link-indicator'][contains(.,'View IP Detail')]"))).click()

  • Using XPATH and the textContext of preceding element:

    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//span[contains(.,'ISP')]//following::span[@class='link-indicator'][contains(.,'View IP Detail')]"))).click()

  • Note: You have to add the following imports :

    from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Upvotes: 2

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