CODEWITHSUNDEEP
pythonfloating-point
Jamba
Jamba

Reputation: 69

How to round float down to 3 decimal places?

I wrote a function to return the energy of a given wavelength. When I run the function the print statement returns the float E, but returns 20+ decimals and I cannot figure out how to round it down.

def FindWaveEnergy(color, lam):
  c = 3.0E8
  V = c/lam
  h = 6.626E-34
  E = h*V
  print("The energy of the " + color.lower() + " wave is " + str(E) + "J.")
FindWaveEnergy("red", 6.60E-7)

I tried doing this:

def FindWaveEnergy(color, lam):
  c = 3.0E8
  V = c/lam
  h = 6.626E-34
  E = h*V
  print("The energy of the " + color.lower() + " wave is " + str('{:.2f}'.format(E)) + "J.")
FindWaveEnergy("red", 6.60E-7)

But that returned 0.000000J. How can I fix my program to return 3 decimal places?

The program returns an E value. i.e. 3.10118181818181815e-19J. I want it to return something like 3.1012e-19J with fewer decimal places.

Upvotes: 0

Views: 275

Answers (2)

Sico-CD
Sico-CD

Reputation: 36

You are actually nearly there. I found this Question

So all you have to do is change

str('{:.2f}'.format(E))

to

str('{:.3g}'.format(E))

Upvotes: 2

dimay
dimay

Reputation: 2804

Try this:

def FindWaveEnergy(color, lam):
  c = 3.0E8
  V = c/lam
  h = 6.626E-34
  E = str(h*V).split("e")
  print("The energy of the " + color.lower() + " wave is " + E[0][:4] + "e" + E[-1] + "J.")
FindWaveEnergy("red", 6.60E-7)

or you can :

print("The energy of the " + color.lower() + " wave is " + str('{:.2e}'.format(E)) + "J.")

Upvotes: 0

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