Reputation: 3158
You are given an array of desired filenames in the order of their creation. Since two files cannot have equal names, the one which comes later will have an addition to its name in a form of (k), where k is the smallest positive integer such that the obtained name is not used yet.
Return an array of names that will be given to the files.
Example
For names = ["doc", "doc", "image", "doc(1)", "doc"], the output should be fileNaming(names) = ["doc", "doc(1)", "image", "doc(1)(1)", "doc(2)"].
One person posted this solution:
const fileNaming = names => {
const used = {};
return names.map(name => {
let newName = name;
while (used[newName]) {
newName = `${name}(${used[name]++})`;
}
used[newName] = 1;
return newName;
});
};
I'm having a hard time understanding the while
block's condition.
used
is an empty object.
newName
is a new variable that is equal to the current item in the names
array.
How does used[newName]
resolve to a number? used
is never set to anything other then an empty object.
This is the console output for console.log(used[newName])
Using this input:
["dd",
"dd(1)",
"dd(2)",
"dd",
"dd(1)",
"dd(1)(2)",
"dd(1)(1)",
"dd",
"dd(1)"]
Upvotes: 2
Views: 427
Reputation: 17955
In JavaScript, {}
is an empty object - and as such, it can contain any number of key-value pairs. A key that is not defined has the value undefined
, which evaluates to false
when tested. However, any non-zero, non-NaN numerical value will evaluate to true
:
console.log({}["a key that does not exist"]) // undefined
while (undefined) {
console.log("this should never be printed"); // never executes
}
while ({}["a key that does not exist"]) {
console.log("this should never be printed"); // never executes
}
if (1) {
console.log("positive numbers are true"); // writes to console
}
You can use objects as maps (even though you can also use actual maps instead in newer code)
A simpler version of the above program would have written
return names.map(name => {
let newName = name;
while (used[newName] !== undefined) { // tests for "not undefined"
newName = `${name}(${used[name]})`; // uses current value
used[name] = used[name] + 1; // sets a larger value
}
used[newName] = 1; // sets a value
return newName;
});
Upvotes: 1