CODEWITHSUNDEEP
phparraysparametersmethod-parameters
daGrevis
daGrevis

Reputation: 21333

How to Convert Array to Params of Method?

I need to pass params (like: 'param1', 'param2', 'param3') to the method... but I have array of params (like: array('param1', 'param2', 'param3')). How to convert array to params?

function foo(array $params) {

    bar(
        // Here should be inserted params not array.
    );

}

Upvotes: 3

Views: 5264

Answers (3)

RoCkHeLuCk
RoCkHeLuCk

Reputation: 329

You can convert one to the other like this:

function foo(array $params)
{
    bar(...$params);
}

or go straight to bar:

bar(...$array);

For the "bar" function to receive several parameters you can use:

function bar(...$params)
{
    //$params is a array of parameters
}

or

function bar($p1, $p2, $p3)
{
    //$pn is a variables
}

or

function bar($p1, ...$pn)
{
    //$p1 is a variable
    //$pn is a array of parameters
}

but a lot of attention with the types and quantity of parameters to not give you problems.

visite: Function Arguments

Upvotes: 1

Adrian World
Adrian World

Reputation: 3128

If you know the param names you could to the following

$params = array(
    'param1' => 'value 1',
    'param2' => 'value 2',
    'param3' => 'value 3',
);

function foo(array $someParams) {
    extract($someParams);  // this will create variables based on the keys

    bar($param1,$param2,$param3);
}

Not sure if this is what you had in mind.

Upvotes: 1

ComFreek
ComFreek

Reputation: 29424

Use the function call_user_func_array.

For example:

call_user_func_array('bar', $params);

Upvotes: 5

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