CODEWITHSUNDEEP
javascript
Piipperi800
Piipperi800

Reputation: 85

Using array to check is an item included in string?

I was thinking about doing an array to make my current string.includes() || string.includes()... code shorter, as checking for many words can make that list long, but I couldn't find an easy way to replicate this with array.

array.includes(string) only seems to check is the string specifically that, so if there's something else in that string too it wont work, which is pretty much the opposite of what I'm trying to do.

Help much appreciated.

Upvotes: 0

Views: 56

Answers (2)

luckongas
luckongas

Reputation: 1799

You could try this

const myString = "Hello";
const arrayOfStrings = ["H", "U", "W"];

const hasString = arrayOfStrings.some(el => myString.includes(el))

console.log(hasString)

Upvotes: 2

SomoKRoceS
SomoKRoceS

Reputation: 3043

It seems like you don't only want to make string.includes() || string.includes()... shorter, but you also want to output all strings that are a substring as a collection, you can use map and filter falsey outputs, like this:

let array = ["ab", "a", "abc", "abd", "cd", "ce"];

let res = array.map(e=>"abcdef".includes(e)?e:null).filter(e=>e!=null)

console.log(res);

If you still want true/false output, you can use reduce, like this:

let array = ["ab", "a", "abc", "abd", "cd", "ce"];

let res = array.map(e=>"abcdef".includes(e)).reduce((a,b)=>a||b,false)

console.log(res);

Upvotes: 1

Related Questions