Reputation: 565
I'd like to call a lambda with const template value, in example below I should write lambdaTemplate
correctly
#include <iostream>
using namespace std;
template<int bar, int baz>
int foo(const int depth) {
return bar + baz + depth;
}
int main() {
////// call function
cout << foo<1, 2>(10) << endl; // 13
///// call lambda without template value
const auto lambda1 = [&](const int v) {
return foo<1, 2>(v);
};
cout << lambda1(10) << endl; // 13
///// call lambda with template value
const auto lambdaTemplate = [&]<A,B ??? >(const int v) { // <-- ERROR doesn't compile
return foo<A,B>(v);
};
cout << lambdaTemplate<1,2>(10) << endl;
return 0;
}
Upvotes: 4
Views: 4132
Reputation: 992
You can define lambda like this :
auto lambdaTemplate = [&]<int T1, int T2>(const int v) {
return foo<T1, T2>(v);
};
and call it like
std::cout << lambdaTemplate.operator()<1,2>(10);
Upvotes: 8