CODEWITHSUNDEEP
pythonpython-3.xselenium
Hyuk
Hyuk

Reputation: 21

I can't get all the <a> tags in selenium python

I need to get all the text inside the <a> tags, but I can get only the text of the first <a> tag.

Here is my code:

table_page = driver2.find_elements_by_class_name('paging')
for tn in table_page: 
    num = tn.find_element_by_class_name('paper.page_link')
    print(num.text)

and this is the HTML code:

<div class="paging">
    <em class=" link_page" style="cursor:pointer"> 1 </em>
    <a class="paper page_link" href="javascript:" url="./detail_nbid" page_num="2">2</a>
    <a class="paper page_link" href="javascript:" url="./detail_nbid" page_num="3">3</a>
</div>

what I expected is 2, 3 but I get only 2.

Upvotes: 1

Views: 112

Answers (3)

costaparas
costaparas

Reputation: 5237

If you select by class name, then you can only specify a class name. This doesn't give you the required flexibility you need here.

Try selecting by CSS Selector.

Here, you are interested in a tags with the class's paper and page_link.

For example:

for a in driver.find_elements_by_css_selector('a.paper.page_link'):
    print(a.text)

Output:

2
3

Upvotes: 1

Arundeep Chohan
Arundeep Chohan

Reputation: 9969

If you want to print all a tags in all paging classes.

table_page = driver2.find_elements_by_class_name('paging')
for tn in table_page: 
    nums = tn.find_elements_by_class_name('paper.page_link')
    for num in nums:
        print(num.text)

Otherwise

table_page = driver2.find_element_by_class_name('paging')
nums = table_page.find_elements_by_class_name('paper.page_link')
for num in nums:
    print(num.text)

Upvotes: 0

nkkumawat
nkkumawat

Reputation: 693

There is typo in your html code. in href your " are not matching.

<div class="paging">
    <em class="link_page" style="cursor:pointer;"> 1 </em>
    <a class="paper page_link" href="javascript:url='./detail_nbid'" page_num="2">2</a>
    <a class="paper page_link" href="javascript:url='./detail_nbid'" page_num="3">3</a>
</div>

Upvotes: 0

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