CODEWITHSUNDEEP
javaandroid
Ammad Ali
Ammad Ali

Reputation: 2216

how to parse inner tag of xml in android

This is my xml. please tell me DOM parse method to parse the whole video tag. actually it has an inner tag of location that is disturbing me.

<video>
    <video_id>39</video_id>
    <title>test video</title>
    <description>asdasd asd as</description>
    <address/>
    <location>
        <longitude>-86.785012400000030</longitude>
        <latitude>33.353920000000000</latitude>
    </location>
    <phone>2055555555</phone>
    <website>http://www.google.com</website>
    <time>154</time>
    <youtube_url>http://www.youtube.com/watch?v=sdfgd</youtube_url>
    <youtube_video_id>sdfgd</youtube_video_id>
    <category_name>User Content</category_name>
    <category_id>48</category_id>
</video>

Upvotes: 0

Views: 504

Answers (2)

Mark Fisher
Mark Fisher

Reputation: 9886

Here's an example reading your xml into a Document object and then using xpath to evalute the text content of the longitude node. Ensure that the video.xml is in the classpath of app (put it in same directory as the java).

I only add the xpath as a point of interest to show you how to query the Document returned.

public class ReadXML {

    private static final DocumentBuilderFactory DOCUMENT_BUILDER_FACTORY = DocumentBuilderFactory.newInstance();
    private static final XPathFactory XPATH_FACTORY = XPathFactory.newInstance();

    public static void main(String[] args) throws Exception {
        new ReadXML().parseXml();
    }

    private void parseXml() throws Exception {
        DocumentBuilder db = DOCUMENT_BUILDER_FACTORY.newDocumentBuilder();
        InputStream stream = this.getClass().getResourceAsStream("video.xml");
        final Document document = db.parse(stream);
        XPath xPathEvaluator = XPATH_FACTORY.newXPath();
        XPathExpression expr = xPathEvaluator.compile("video/location/longitude");
        NodeList nodes = (NodeList) expr.evaluate(document, XPathConstants.NODESET);
        for (int i = 0; i < nodes.getLength(); i++) {
            Node item = nodes.item(i);
            System.out.println(item.getTextContent());
        }
    }

}

Upvotes: 0

Rupok
Rupok

Reputation: 2082

This tutorial might help you http://www.androidpeople.com/android-xml-parsing-tutorial-using-saxparser

Upvotes: 2

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