CODEWITHSUNDEEP
javascriptgoogle-cloud-firestoreasync-await
user3111472
user3111472

Reputation: 207

Javascript Then() Promise is not working Asynchronously

I'm trying to figure out how to make this Firestore Collection asynchronously. I currently have it in a recursive function because a for loop wasn't working either. I thought by using a recursive function it would give me more control for when I wanted to start the function over, but it's still not working. Please help. I know this would be something easy to solve for most people.

const fakeIt = async () => {
    console.log("A");
    
    var itemsCreated = 1;
    items(0, itemsCreated);
    
    async function items(num, itemsCreated){
        if(num < itemsCreated){
            console.log("B");
            
            await db.collection('items').add({
                          active: true
            }).then(async (item) => {
                console.log("C");
                items(num + 1, itemsCreated)
            });
        }else{
            console.log("Done");
        }
    }
}
Array(2).fill(0).forEach(fakeIt);

The print out I'm getting is as follow:

A
B
A
B
C
Done
C
Done

I need the result of:

A
B
C
A
B
C
Done

Upvotes: 0

Views: 90

Answers (1)

user3111472
user3111472

Reputation: 207

I figured it out by using a recursive function for the fakeIt loop. I got rid of all of the async-await and everything works perfectly. Thank to those that made the comments above.

function fakeIt(number, count) {

     if (number < count) {

          console.log("A");
    
          var itemsCreated = 1;
          items(0, itemsCreated);
    
          function items(num, itemsCreated){

               if(num < itemsCreated){
                    console.log("B");
            
                   db.collection('items').add({
                          active: true
                    }).then(async (item) => {
                         console.log("C");
                         items(num + 1, itemsCreated)
                    });
               }else{

                    fakeIt(number+1, count)
               }
       }else{

            console.log("Done");
       }
}
fakeIt(0, 2)

Upvotes: 1

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