CODEWITHSUNDEEP
pythonstringpalindrome
CompactSpaces
CompactSpaces

Reputation: 3

Palindrome in Python operating on strings only

I am trying to write a program in Python which will detect that the word given by a user is a palindrome or not.

Here is my code - I operate only on strings - my solution is totally different that other which I have seen here or anywhere, thus I would like you - StactOverFlow users ;) - to check its correctness.

I needn't say that I am not a pro, having rather basic knowledge. However, I would be glad if anyone spend their time and give me some feedback.

# a palindrome
string = input('word: ')
if(len(string) % 2 != 0):
  left = string.lower()[0:int((len(string)-1)/2)]
  right = string.lower()[int((len(string)-1)/2 + 1): ]
  if left == right[::-1]:
    print('{} is a palindrome'.format(string.lower()))
  else:
    print('{} is not a palindrome'.format(string))
else:
  left = string.lower()[0:int((len(string)/2))]
  right = string.lower()[int(len(string)/2):]
  if left == right[::-1]:
    print('{} is a palindrome'.format(string.lower()))
  else:
    print('{} is not a palindrome'.format(string.lower()))

Upvotes: 0

Views: 147

Answers (2)

Synthaze
Synthaze

Reputation: 6090

Here you get a oneliner that prints out the palindromes:

print ([v for v in palindromes_test if (len(v) % 2 == 0 and v[0:len(v)//2] == v[len(v)//2:][::-1]) or (len(v) % 2 != 0 and v[0:len(v)//2] == v[len(v)//2+1:][::-1])])

Otherwise:

palindromes_test = ['ABCDCBA','EVE','ABCABC']

for elem in palindromes_test:
    if len(elem) % 2 == 0 and elem[0:len(elem)//2] == elem[len(elem)//2:][::-1]:
        print ("%s palindrome" % elem)
    elif len(elem) % 2 != 0 and elem[0:len(elem)//2] == elem[len(elem)//2+1:][::-1]:
        print ("%s palindrome" % elem)
    else:
        print ("%s not palindrome" % elem)

Output:

ABCDCBA palindrome
EVE palindrome
ABCABC not palindrome

Upvotes: 0

Daphoque
Daphoque

Reputation: 4678

To detect a palindrome just check if the reverse string is equal to the original one

palindromes_test = ['ABCDCBA','EVE','ABCABC']

print ([v for v in palindromes_test if (v == (v[::-1]))])

output

 ['ABCDCBA', 'EVE']

Upvotes: 1

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