Reputation: 67
I just wanted to know if it is considered good practice to nest promises like in this example, or is there better alternatives ?
getDatabaseModel.searchId(idNoms).then(function([noms, elements]) {
getDatabaseModel.getLocalisations().then(function(localisations){
getDatabaseModel.getStates().then(function(states){
//Some code
})
})
})
Upvotes: 2
Views: 103
Reputation: 14208
Obviously, your promises are independent. So you should use Promise.all()
to make it run parallel with the highest performance.
The Promise.all() method takes an iterable of promises as an input, and returns a single Promise that resolves to an array of the results of the input promises
var searchById = getDatabaseModel.searchId(idNoms);
var getLocalisations = getDatabaseModel.getLocalisations();
var getStates = getDatabaseModel.getStates();
var result = Promise.all([searchById, getLocalisations, getStates]);
result.then((values) => {
console.log(values);
});
For example, Let's say each promise takes 1s - So it should be 3s in total, But with Promise.all
, actually it just takes 1s in total.
var tick = Date.now();
const log = (v) => console.log(`${v} \n Elapsed: ${Date.now() - tick}`);
log("Staring... ");
var fetchData = (name, ms) => new Promise(resolve => setTimeout(() => resolve(name), ms));
var result = Promise.all(
[
fetchData("searchById", 1000),
fetchData("getLocalisations", 1000),
fetchData("getStates", 1000)
]);
result.then((values) => {
log("Complete...");
console.log(values);
});
Besides, If you're concern about asyn/await with more elegant/concise/read it like sync code, then await
keyword much says the code should wait until the async request is finished and then afterward it'll execute the next thing. While those promises are independent. So promise.all
is better than in your case.
var tick = Date.now();
const log = (v) => console.log(`${v} \n Elapsed: ${Date.now() - tick}`);
var fetchData = (name, ms) => new Promise(resolve => setTimeout(() => resolve(name), ms));
Run();
async function Run(){
log("Staring... ");
var a = await fetchData("searchById", 1000);
var b = await fetchData("getLocalisations", 1000);
var c = await fetchData("getStates", 1000);
log("Complete...");
console.log([a, b, c]);
}
Upvotes: 3
Reputation: 16450
IMO it's a little hard to read and understand. Compare with this:
getDatabaseModel.searchId(idNoms)
.then(([noms, elements]) => getDatabaseModel.getLocalisations())
.then(localization => getDatabaseModel.getStates());
As @deceze pointed out there are two things to note:
noms
, elements
and localization
are not used at all.With Promise.all
you can mix and match however you want:
// Call `searchId` and `getState` at the same time
// Call `getLocalisations` after `searchId` is done
// wait for all to finish
Promise.all([
getDatabaseModel.searchId(idNoms).then(([noms, elements]) => getDatabaseModel.getLocalisations()),
getDatabaseModel.getStates()
]).then(([result1, result2]) => console.log('done'));
// Call all 3 at the same time
// wait for all to finish
Promise.all([
getDatabaseModel.searchId(idNoms),
getDatabaseModel.getLocalisations(),
getDatabaseModel.getStates(),
]).then(([result1, result2, result3]) => console.log('done'));
Upvotes: 2
Reputation: 2044
Promises were made to avoid callback hell, but they are not too good at it too. People like promises until they find async/await. The exact same code can be re-written in async/await as
async getModel(idNoms){
const [noms, elements] = await getDatabaseModel.searchId(idNoms);
const localisations = await getDatabaseModel.getLocalisations();
const state = await getDatabaseModel.getStates():
// do something using localisations & state, it'll work
}
getModel(idNoms);
Learn async/await here
Upvotes: 3