Reputation: 43
I want to convert date of birth from a text file.Let's say, I have data
fjsffk 1985-01-30
fkgskgks 1899-02-20
I have tried with the following code, still getting error:
import datetime
months = ['January', 'February', 'March', 'April', 'May', 'June', 'July',
'August', 'September', 'October', 'November', 'December']
with open('file.txt', 'r') as f:
for line in f.readlines():
dob = line.rsplit(None, 1)[-1]
dt = datetime.strptime(dob, "%Y-%m-%d")
print "{0:} {1:}, {2:}".format(months[dt.month-1], dt.day, dt.year)
Any solution please, thanks!
Upvotes: 4
Views: 6788
Reputation: 29121
As per python tutorial
The exact range of years for which strftime() works also varies across platforms. Regardless of platform, years before 1900 cannot be used.
Please bear with me - i have tried the following solution and it works fine for me:
from datetime import datetime
mDt = datetime(1900,01,01)
dt = datetime.strptime('20-02-1899', "%d-%m-%Y")
resultString = datetime(dt.year + (mDt - dt).days/365 + 1, dt.month, dt.day).strftime('%B %d, %Y').replace('1900', str(dt.year))
OR something like this:
monthes = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
dt = datetime.strptime('20-02-1890', "%d-%m-%Y")
print "{0:} {1:}, {2:}".format(monthes[dt.month-1], dt.day, dt.year)
Upvotes: 8
Reputation: 1354
Here is a previous post that may have some ideas for you: formatting-date-string-in-python-for-dates-prior-to-1900
Upvotes: 0